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Rus_ich [418]
3 years ago
10

Given a graph, with no equation, how can you graph the inverse?

Mathematics
1 answer:
patriot [66]3 years ago
4 0

There are two different ways you can do this, I have provided both below.

Answer: You can switch all the x and y coordinate values.

   For example, if you have (2, 1) you would graph (1, 2).

       Another example, if you have (677, 83) you would graph (83, 677)

Answer: Flip the graph over the line of y = x

   I have attached an example from<em> lumenlearning.com</em>.

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Whats the answer for this ​
marysya [2.9K]
The answer is c hope this helps
6 0
3 years ago
Pls answer i will give brightest
antoniya [11.8K]

Answer:

choice 1

Step-by-step explanation:

A= 250 m²

Each triangle gets:

250/4= 62.5 m²

l=12 m, h= 10.4 m ⇒ A= 1/2*12*10.4 m²= 62.4 m² is the correct option, the rest give greater area

6 0
3 years ago
What is the measure of angle 1?<br><br> A. 90<br> B. 45<br> C. Not enough info<br> D. 180
Anettt [7]

Answer:

C ig.

Step-by-step explanation:

well, it's not a right angle (90 degrees), it's not a 45 degree angle, and it's not a straight angle (180 degrees), so it's not enough info

3 0
3 years ago
Read 2 more answers
8
Nata [24]

Answer: 15, -8

Step-by-step explanation:

u_2=7\\u_2=u_1+r\\u_3=u_1+2r\\u_4=u_1+3r\\\\u_1+u_2+u_3+u_4=4u_1+6r=12\\u_1+r=7\\\\

\left \{ \begin {array} {ccc|c|c}u_1+r&=&7&-4&-6\\4u_1+6r&=&12&1&1\\\end {array} \right.\\\\\\\left \{ \begin {array} {ccc}2r&=&-16\\-2u_1&=&-30\\\end {array} \right.\\\\\\\left \{ \begin {array} {ccc}r&=&-8\\u_1&=&15\\\end {array} \right.\\\\\\Proof:\\u_1=15\\u_2=7\\u_3=-1\\u_4=-9\\sum=12\\

6 0
3 years ago
Two spherical shells have their mass uniformly distrubuted over the spherical surface. One of the shells has a diameter of 2 met
ivann1987 [24]
The moment of inertia of a spherical shell is I = mr²

If two spheres have the same moment of inertia, then
I₁ = I₂
m₁(r₁)² = m₂(r₂)²

Solve for the second mass:
m₂ = m₁ (r₁/r₂)²

Given m₁ = 1 kg, r₁ = 2 m, r₂ = 1m,
m₂ = (1 kg) (2 m / 1 m)² = 4 kg

7 0
3 years ago
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