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3 years ago

Y = (x) = (1/16)^x Find f(x) when x = (1/4)

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

8 0

Answer is 0.5
Here it is step-by-step

Naddik [55]3 years ago

7 0

Answer:

1/2

Step-by-step explanation:

(1/16)^x

Let x = 1/4

(1/16)^ 1/4

Rewriting 16 as 2^4

(1/2^4)^ 1/4

We know that 1 / a^b = a^-b

(2 ^ -4)^ 1/4

We know that a^b^c = a^(b*c)

2^(-4*1/4)

2^-1

We know that a^-b = 1/ a^b

2^-1 = 1/2^1 = 1/2

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Step-by-step explanation:

The slope intercept form is y = mx + b.

First, find the slope. Use rise/run which gives you -7. <= negative bc its a negative slope.

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3 years ago

How many solutions does 6x−1=34−x have

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Step-by-step explanation:

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3 years ago

There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl

Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

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4 years ago

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Answer:

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Step-by-step explanation:

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