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2 years ago

Y = (x) = (1/16)^x Find f(x) when x = (1/4)

Mathematics

2 answers:

jok3333 [9.3K]2 years ago

8 0

Answer is 0.5
Here it is step-by-step

Naddik [55]2 years ago

7 0

Answer:

1/2

Step-by-step explanation:

(1/16)^x

Let x = 1/4

(1/16)^ 1/4

Rewriting 16 as 2^4

(1/2^4)^ 1/4

We know that 1 / a^b = a^-b

(2 ^ -4)^ 1/4

We know that a^b^c = a^(b*c)

2^(-4*1/4)

2^-1

We know that a^-b = 1/ a^b

2^-1 = 1/2^1 = 1/2

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A study is done to find the 95% confidence interval for the difference in means between the ACT scores between two schools in a

Kitty [74]

Solution :

95% confidence interval for the difference between the means of ACT scores between two schools, is given by :

$[(\overline X_1 - \overline X_2)-ME, (\overline X_1 - \overline X_2)+ME]$

$\overline X_1 = 25.90 , \ \ \ \overline X_2 = 27.70$

$S_1=3.49, \ \ \ S_2 = 2.47$

$n_1=39, \ \ n_2=37$

M.E. , Margin of error,

$=t_{n_1+n_2-2,0.025} \times \left( s \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}$

$s^2 = \frac{(n_1-1)S_1^2+(n_2-1)S^2_2}{n_1+n_2-2}$

$=\frac{38(3.49)^2+36(2.47)^2}{39+37-2}$

= 9.222

s = 3.03

$t_{74,0.05} = 1.99$

$M.E. = 1.99 \times 3.03 \times \sqrt{\frac{1}{39}+\frac{1}{37}}$

= 1.4

Therefore, 95% CI = [(25.90-27.70) - 1.4 , (25.90-27.70) + 1.4]

= [-3.2, -0.4]

Therefore, the lower bound is -3.2

7 0

2 years ago

What's the area of the triangle with 9mm 76mm 100mm

svlad2 [7]

9514 1404 393

Answer:

342 mm²

Step-by-step explanation:

The triangle shown has a base of 9 mm and a height of 76 mm. Its area is ...

A = 1/2bh

A = (1/2)(9 mm)(76 mm) = 342 mm²

The triangle shown has an area of 342 mm².

_____

Additional comment

The other leg of the right triangle with one leg 76 mm and hypotenuse 100 mm will be about 65 mm. The base shown is 9 mm, so any triangle with the dimensions shown will be a fairly skinny obtuse triangle, not the acute triangle in the picture. (This makes us suspect an error: the 9 mm dimension maybe should be 90 mm.)