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o-na [289]
3 years ago
7

35 hours a week (5 days).how many hours per day?​

Mathematics
1 answer:
dolphi86 [110]3 years ago
3 0

Answer:

7 Hours per day

Step-by-step explanation:

35/5=7

If you are working 35/hrs a week, and you only work 5 days, to find out how many hours you work each day, you need to divide the amount of hours per week and the days per week.

Hence, 35/5=7.

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a system of equations is shown below: equation a: 2c = d − 8 equation b: c = 3d 8 which of the following steps should be perform
Fofino [41]
If you would like to know which of the following steps should be performed to eliminate variable d first, you can find this using the following steps:

equation a: 2c = d - 8      /*(-3)
equation b: c = 3d + 8
__________________
-6c = -3d + 24
c = 3d + 8
__________________
-6c + c = -3d + 24 + 3d + 8
-5c = 32
5c = -32
c = -32/5

<span>The correct result would </span>be: <span>multiply equation a by −3.</span>
3 0
4 years ago
What are these??<br><br>Find x. Simplify the Radical or Round to the nearest. <br><br>​
omeli [17]
A2 + b2 = c2

Number 1 is 15.1986.... or 15.2

Explanation: 5 squared is 25 and 16 squared is 256. Subtract 256 minus 25 to get 231, then divide it by the square root.

Number 2 is 7.21111.... or 7.2
Explanation: 6 squared plus 4 squared is 52, square root of 52= 7.2
3 0
3 years ago
Read 2 more answers
What is c/6=9 equals to
Julli [10]

c = 54

!!!_!£((£2((2)1)1)1

5 0
3 years ago
My little cuz need help can you help her please
Valentin [98]

Answer: x=-3 and y= -15

Step-by-step explanation: 1 Substitute y=5xy=5x into 4x-2y=184x−2y=18.

-6x=18

−6x=18

2 Solve for xx in -6x=18−6x=18.

x=-3

x=−3

3 Substitute x=-3x=−3 into y=5xy=5x.

y=-15

y=−15

4 Therefore,

\begin{aligned}&x=-3\\&y=-15\end{aligned}

​

 

x=−3

y=−15

​

7 0
3 years ago
Read 2 more answers
Justin got a gift card to Cold Stone Creamery. Every time he goes, he gets an ice cream sundae, and it costs $6.75. If he bought
kicyunya [14]

Answer:

27

Step-by-step explanation:

27, because 6.75*4=27

4 0
3 years ago
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