Answer:
B=112 degrees A=68 degrees and C=68 degrees
Step-by-step explanation:
the opposite angle of the 112-degree angle is the angle on the top left of the page, this means both of the angles are the same. You can then tell that that angle is the same as the one across from it because it shows on the page. You can then figure out the opposite angle which is B so that means angle B is equal to 112 degrees. To figure out angle A you can just do 180 minus the angle B which is 112 degrees. You now know angle A which is 68 degrees, now to find the angle C you just have to notise that angle C is the opposite angle of angle A. This means that algle C is also 68 degrees.
The total volume of the 40 sphere shaped water balloons is 46032.38 cubic cm.
Radius of 1 sphere = 6.5 cm
We know that the volume of the sphere is given by 4/3 π r³
We will take the radius as 6.5 cm and π as 22/7
Now we will find the volume : 4/3 ×22/7×6.5³ = 1150.81 cubic cm.
Volume of 40 such spheres = 40 × 1150.81 = 46032.38 cubic cm.
The radius of all the spheres are 46032.38 cubic cm.
A sphere is a geometrical entity with three dimensions that resembles a two-dimensional circle. A sphere is a group of points in three dimensions that are all situated at the same r-distance from one another.
The supplied point is the sphere's center, while the letter r stands for the sphere's radius which is half the diameter. The earliest known allusions to spheres are found in the works of two ancient Greek mathematicians.
Therefore total volume of the 40 sphere shaped water balloons is 46032.38 cubic cm .
Disclaimer: The complete question is : Maggie and Amelia filled up 40 water balloons shaped like spheres. Each water balloon had a radius of 6.5 cm.Find the total volume of water required.
To learn more about sphere visit:
brainly.com/question/9994313
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Answer:
hmmmmmm
Step-by-step explanation:2
Interest = Principle(Rate)(Time)
$84.50 = P(0.0325)(4)
$84.50 = P(0.13)
$84.50/0.13 = P
P = 650
$650 was originally deposited.
Answer: 
Step-by-step explanation:
The circular oil slick is expanding at a rate of 
Let A be the area of the circular oil slick,
So, the changes in A with respect to time (t),
Also, the change in diameter with respect to time(t),
For r = 1.5 m,
![\frac{d}{dt} ( 2 r)]_{r=1.5} = \frac{2}{\pi \times 1.5}=\frac{20}{\pi \times 15}=\frac{4\pi }{3}\text{ meter per hour}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%28%202%20r%29%5D_%7Br%3D1.5%7D%20%3D%20%5Cfrac%7B2%7D%7B%5Cpi%20%5Ctimes%201.5%7D%3D%5Cfrac%7B20%7D%7B%5Cpi%20%5Ctimes%2015%7D%3D%5Cfrac%7B4%5Cpi%20%7D%7B3%7D%5Ctext%7B%20meter%20per%20hour%7D)
