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2 years ago

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The overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 7.8 c

m. a. Find the probability that an individual distance is greater than 218.00 cm. b. Find the probability that the mean for 25 randomly selected distances is greater than 204.20 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? a.

1 answer:

Kobotan [32]2 years ago

6 0

Answer:

its b ive had this question before

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Find the partial fraction decomposition of

Gwar [14]

$\dfrac1{x(x-1)}=\dfrac ax+\dfrac b{x-1}$

$1=a(x-1)+bx$

If $x=0$ , then

$1=-a\implies a=-1$

If $x=1$ , then

$1=b$

So we have

$\dfrac1{x(x-1)}=\dfrac1{x-1}-\dfrac1x$

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3 years ago

The sum of two numbers is 2. Their difference is -16. What is the first number?

Helen [10]

Answer: The first number is 4

Explanation: Since the sum of the two numbers is ten, x + y = 10

Also, since the difference of the two numbers is two, then x - y = 2

Since x - y = 2, another way to write that is x = y + 2 and since x is exactly the same as y + 2, we can plug in "y + 2" in place of x in the first equation (x + y = 10) to get (y + 2) + y = 10. Then we solve this equation by combining like-terms.

2y + 2 = 10

2y = 8

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Since x = y + 2, x = 4 + 2 or x = 6

I hope this helped you!

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3 years ago

Read 2 more answers

How can you find the equation of a line that is parallel/perpendicular to a given line

alexdok [17]

In the Slope-Intercept Form, m is the slope and b is the y-intercept.

<u>Finding The Equation of a Line Parallel to the Given Line:</u> Let the given line be line a and the parallel line be line b.

1) Find the slope of line a.

Example: Line a --> $y = 5x + 2$ . The slope is 5.

2) Find the y-intercept of line b.

To do this, you need to be given the coordinates of a point located on line b.

Example: The slope is 5 and the point is (2, 3), use the Slope-Intercept Formula, $y=mx+b$ ---> $3 = 5(2) + b$ . Then you solve for b.

$3 = 5(2) + b$

$3 = 10 + b$

$3 - 10 = 10 - 10 + b$

$-7 = b$ $b=-7$

The y-intercept of line b is -7

3) Finally, plugin the slope and the y-intercept into the Slope-Intercept Form.

Example: The slope of line b is 5 and the y-intercept is -7. The equation of line b is $y = 5x - 7$ .

<u>Finding The Equation of a Line Perpendicular to The Given Line:</u> Let the given line be line a and the perpendicular line be line b.

1) Find the opposite reciprocal of the slope of line a.

Example: Line a --> $y=5x+2$ . The slope is 5, to find the opposite reciprocal of the slope you use n --> $-\frac{1}{n}$ . In this case, it would be $-\frac{1}{5}$ . The opposite reciprocal of the slope of line a is $-\frac{1}{5}$ , which would be the slope of line b.

2) Find the y-intercept of line b.

To do this, you need to be given the coordinates of the point where line a and line b both intersect.

Example: The slope of line b is $-\frac{1}{5}$ and the point is (1, 7), use the Slope-Intercept Formula, $y=mx+b$ ---> $7=-\frac{1}{5}(1) + b$ . Then you solve for b.

$7=-\frac{1}{5}(1) + b$

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$7\frac{1}{5} =b$ $b=7\frac{1}{5}$

The y-intercept of line b is $7\frac{1}{5}$ .

3) Finally, plugin the slope and the y-intercept into the Slope-Intercept Form.

Example: The slope of line b is $-\frac{1}{5}$ and the y-intercept is $7\frac{1}{5}$ . The equation of line b is $y=-\frac{1}{5}x+7\frac{1}{5}$ .

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3 years ago

Find the slope of the line that passes through (3, 8) and (8, 5).

tino4ka555 [31]

Answer:

-⅗

Step-by-step explanation:

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3 years ago

Absolute value of 2c + 8 = absolute value of 10 c

Radda [10]

-2c - 8 = -10c
+2c +2c
-8 = -8c
divide by -8
1 = c

2c + 8= 10c
-2c -2c
8 = 8c
divide by 8
1 =c

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3 years ago