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1 year ago

Is the difference of 1/5 and 1/10 is closer to 1/2 than to 0?

Mathematics

2 answers:

Fudgin [204]1 year ago

8 0

Answer:

farther

Step-by-step explanation:

valentinak56 [21]1 year ago

3 0

The difference of 1/5 and 1/10 is closer to 0, the difference is 1/10

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Three consecutive even integers have a sum of -48. Find the largest integer.

kobusy [5.1K]

Answer:

Step-by-step explanation:

{x - some integer}

2x - the first even integer

2x+2 - the second consecutive even integer

2x+4 - the third consecutive even integer (the largest)

2x + 2x+2 + 2x+4 - the sum of three consecutive even integers

2x + 2x+2 + 2x+4 = -48

6x + 6 = -48

÷3 ÷3

2x + 2 = -16

+2 +2

2x+4 = -14

6 0

3 years ago

The hypotenuse of a right

Lina20 [59]

None I would think because none of them are them because if you it is not the

8 0

2 years ago

Solve for x. <br> 7x - 2 = 126

Novay_Z [31]

You’re answer would be x=18.28

7 0

2 years ago

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

5 0

2 years ago

How much money should be invested at 5% interest, compounded quarterly, so that 7 years later the investment will be worth $5000

vampirchik [111]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$5000\\
P=\textit{original amount deposited}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, four times}
\end{array}\to &4\\
t=years\to &7
\end{cases}
\\\\\\
5000=P\left(1+\frac{0.05}{4}\right)^{4\cdot 7}\implies 5000=P(1.0125)^{28}\\\\\\ \cfrac{5000}{(1.0125)^{28}}=P$

8 0

2 years ago