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sertanlavr [38]

3 years ago

13

This data set represents the widths in yards of pieces of fabric used by a sewing group. What is the mean of this data set? {1 1

/3, 1/4, 2/3, 1/2, 1 1/4} Enter your answer as a fraction in simplest form in the box.
hurry

1 answer:

Paha777 [63]3 years ago

5 0

The mean of a dataset is the average or the expected value of the dataset

The mean of the dataset is 4/5

<h3>How to determine the mean</h3>

The dataset is given as: {1 1/3, 1/4, 2/3, 1/2, 1 1/4}

The mean of a dataset is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{1 \frac 13+ \frac 14+ \frac 23+ \frac 12+ 1 \frac 14}{5}$

This gives

$\bar x = \frac{4}{5}$

Hence, the mean of the dataset is 4/5

Read more about mean at:

brainly.com/question/14532771

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It's D. 4

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Y-6=4(x+5) what is y and x intercept?

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Answer:

x = $(-\frac{13}{2} ,0)$ y = (0,26)

Step-by-step explanation:

First find the x intercept

To find the x intercept, substitute 0 for y and solve for x.

$(0)-6=4(x+5)$

Rewrite the equation as $4(x+5)=(0)-6$

$4(x+5)=(0)-6$

Subtract 6 from 0.

$4(x+5)=-6$

Divide each term in $4(x+5)=-6$ by 4.

$\frac{4(x+5)}{4} =\frac{-6}{4}$

Cancel the common factor of 4.

$x+5=\frac{-6}{4}$

Simplify $\frac{-6}{4}$

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Subtract 5 from both sides of the equation.

$x=-\frac{3}{2} -5$

To write $-5$ as a fraction with a common denominator, multiply by $\frac{2}{2}$

$x=-\frac{3}{2}-5$ · $\frac{2}{2}$

Combine $-5$ and $\frac{2}{2}$ .

$x=-\frac{3}{2} +\frac{-5*2}{2}$

Combine the numerators over the common denominator.

$x=\frac{-3-5*2}{2}$

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$x=\frac{-13}{2}$

Move the negative in front of the fraction.

$x=-\frac{13}{2}$

x = $(-\frac{13}{2} ,0)$

-----------------------------------------------------------------------------------------------------

Find the y-intercepts.

To find the y-intercept(s), substitute in 0 for x and solve for y.

$y-6=4((0)+5)$

Add 0 and 5.

$y-6=4 *5$

Multiply 4 by 5.

$y-6=20$

Add 6 to both sides of the equation.

$y=20+6$

Add 20 and 6.

$y=26$

y = (0, 26)

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Read 2 more answers

The lengths of 3-inch nails manufactured on a machine are normally distributed with a mean of 3.0 inches and a standard deviatio

otez555 [7]

Using the normal distribution, it is found that 2.64% of all the nails produced by this machine are unusable.

In a <em>normal distribution</em> with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 3 inches, hence $\mu = 3$ .

The standard deviation is of 0.009 inches, hence $\sigma = 0.009$ .

Nails that are <u>more than 0.02 inches</u> from the mean are unusable, hence:

$Z = \frac{0.02}{\sigma}$

$Z = \frac{0.02}{0.009}$

$Z = 2.22$

The proportion is P(|Z| > 2.22), which is <u>2 multiplied by the p-value of Z = -2.22</u>.

Z = -2.22 has a p-value of 0.0132.

2 x 0.0132 = 0.0264

0.0264 x 100% = 2.64%

2.64% of all the nails produced by this machine are unusable.

You can learn more about the normal distribution at brainly.com/question/24663213

7 0

3 years ago