<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
252 is the answer hope it helps
Answer:
It would be 24.4 pounds.
Step-by-step explanation:
First do: 13.4 / 100 = 0.134
Then, 182 * 0.134,
to get 24.4 pounds.
You can use midpoint formula
M=x1+x2/2 , y1+y2/2
M=-2+4/2 , 2+2/2
M= 1,2
Answer:
It is a reflection across the y axis
Step-by-step explanation:
The reflection of point (x, y) across the x-axis is (x, -y).
The reflection of point (x, y) across the y-axis is (-x, y).
Since (-4, -2.4) becomes (4, -2.4) The x values changes sign. It is a reflection across the y axis
