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Maksim231197 [3]
3 years ago
13

Find the value of x and y.

Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0

X would be 63, Y would be 27

A straight line is 180 degrees. 180-117=63

To find Y, since we know it is a 90 degree angle do 90-63 which is 27.
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Solve the equation by using the quadratic formula. x^2+2x=6​
katrin [286]

Answer:

\Huge \boxed{{x=-1\pm \sqrt{7}}}

Step-by-step explanation:

x² + 2x = 6

Subtract both sides by 6.

x² + 2x - 6 = 0

ax²+bx+c=0

a=1, b=2, and c=-6

We can apply the quadratic formula.

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Plug in the values.

\displaystyle x=\frac{-2\pm\sqrt{2^2-4(1)(-6)}}{2(1)}

Evaluate.

\displaystyle x=\frac{-2\pm\sqrt{4-(-24)}}{2}

\displaystyle x=\frac{-2\pm\sqrt{28}}{2}

\displaystyle x=\frac{-2\pm 2\sqrt{7}}{2}=-1 \pm \sqrt{7}

6 0
3 years ago
What is the 45th term of the sequence generated by the formula (-1) 2n+1 ?
Natalija [7]

Answer:

−0.989010989010

Step-by-step explanation:

what is the 45th term of a sequence generated by the formula tn=(-1)^n * (2n/2n+1)?

When n= 45

tn=(-1)^n*(2n/2n+1)

tn = (-1)^45 * ( 2(45) / 2(45) + 1

= -1 * 90 / (90+1)

= -90 / 91

= −0.989010989010

The 45th term of the sequence generated by the formula tn=(-1)^n*(2n/2n+1) is −0.989010989010

5 0
3 years ago
Tell me something you have wanted to say but never told anyone.
Stells [14]
I’m not that smart i just get answers off the internet
6 0
3 years ago
Does anybody have a REAL answer for this?
S_A_V [24]
Area of square = 15 x 15 = 225 cm^2
area of circle = pi r^2 = (3.14)(15)(15) = 706.5 cm^2

1/4 of circle = 706.5 / 4 = 176.6

so area of yellow region = 225  - 176.6 = 48.4 cm^2

answer
48.4 cm^2
6 0
3 years ago
Let X be a random variable with probability mass function
Naya [18.7K]

Answer:

a. g(x) = ln(x).

b. g(x) = x*e^{xt}

Step-by-step explanation:

By the definition, the expected value of a random variable X with probability mass function p is given by \sum P(X=x)\cdot x where the sum runs over all the posible values of X. Given a function g, the random variable Y=g(X) is defined. Note that the function g induces a probability mass function P' given by P'(Y=k) = P(X=g^{-1}(k)) when the function g is bijective.

a. Note that for 1/3ln(2)+1/6ln(5) by choosing the function g(x) = ln(x) the expression coincides with E(g(x)), because if Y = g(x)  then E(Y) = P'(Y=1)*ln(1)+P'(Y=2)*ln(2)+P'(Y=5)*ln(5) = P(X=1)*ln(1)+P(X=2)*ln(2)+P(X=5)*ln(5).

b. On the same fashion, the function g(x) = xe^{xt} fullfills the expression of E[g(X)]

6 0
3 years ago
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