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sergiy2304 [10]
3 years ago
11

PLEASE PLEASE HELP!!!!!!!! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER! REALLY NEED HELP!

Mathematics
1 answer:
ikadub [295]3 years ago
7 0
The formula for compound interest is A=P(1+r/n)^nt, where n is the number of times an item is being compounded over the length of t, an amount of time, r is the rate of increase, and P is the principle amount (initial amount).

Our Principal, or initial amount is 600,000 and our rate of change is found by
dividing any number in the sequence by another number that is placed lower in the sequence, For example:
<u>r=69000/60000=1.15</u>
We are not given n, so our equation is 600,000(1.15)^n-1

:)
You might be interested in
Find the slope of the following 2 points (2,-5), (9,3)
Rama09 [41]

Answer:

8/7

Step-by-step explanation:

(2,-5) (9,3)

3-(-5)=8 because you apply your keep change change

9-2=  7

so 8/7

4 0
3 years ago
Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married                     21                              37                            58                116

Not Married              59                             63                            42                164

Total                          80                             100                          100              280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married             33.143                       41.429                        41.429                116

Not Married     46.857                      58.571                        58.571                164

Total                   80                              100                             100                 280

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0
3 years ago
Can someone answer this for me
Anastaziya [24]
X=60° (equilateral triangle)

y=120°
Working: (360°-120°)/2
6 0
2 years ago
18.Lupe and her friends spent $20 on snack mix and water. They bought x bags of snack mix and y bottles of water. They bought a
Readme [11.4K]

Answer:

bags of snack = x = 6

bottles of water = y = 5

Step-by-step explanation:

The system of equations can be used to determine how many of each item they bought.

20.00=2.50x+1.00y

11=x+y

how many bags of snack mix did they buy?

Let

bags of snack = x

bottles of water = y

20.00 = 2.50x + 1.00y (1)

11 = x + y (2)

From (2)

x = 11 - y

Substitute x = 11 - y into (1)

20.00 = 2.50x + 1.00y

20.00 = 2.50(11 - y) + 1.00y

20.00 = 27.5 - 2.50y + 1.00y

20.00 - 27.5 = -2.50y + 1.00y

-7.5 = -1.5y

y = -7.5/-1.5

y = 5

Substitute y = 5 into (2)

11 = x + y

11 = x + 5

11 - 5 = x

x = 6

bags of snack = x = 6

bottles of water = y = 5

7 0
3 years ago
(Need help ASAP!) Select the equation that most accurately depicts the word problem.
antiseptic1488 [7]
I the answer is C I’m not really sure but I’ll update u when i get the answer
5 0
2 years ago
Read 2 more answers
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