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sergiy2304 [10]

3 years ago

11

PLEASE PLEASE HELP!!!!!!!! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER! REALLY NEED HELP!

1 answer:

ikadub [295]3 years ago

7 0

The formula for compound interest is A=P(1+r/n)^nt, where n is the number of times an item is being compounded over the length of t, an amount of time, r is the rate of increase, and P is the principle amount (initial amount).

Our Principal, or initial amount is 600,000 and our rate of change is found by
dividing any number in the sequence by another number that is placed lower in the sequence, For example:
<u>r=69000/60000=1.15</u>
We are not given n, so our equation is 600,000(1.15)^n-1

:)

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Convert 28/50to a percent

velikii [3]

The answer is 56%
You first divide 28 by 50=.56, then since it's a decimal, you move the decimal twice to the right to make a percentage=56%

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4 years ago

Find the y intercept and x intercept for the following liner equation -4x-10y=-40

Vinvika [58]

The y intercept is 4, and the x intercept is 0.

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3 years ago

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Natalija [7]

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1 year ago

Suppose thirty-two students signed up for classes during an orientation session. If

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Answer:

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3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago