Writ the whole number in expanded form 29,780,000

What is the experamental probability that the coin lands on heads?

sammy [17]

Answer:

The experamental probability that the coin lands on head is 50 %

Step-by-step explanation:

Given:

Experiment:

A coin is Toss

Let the Sample Space be 'S' that is total number of outcomes for a coin has been tossed = { Head, Tail }

∴ n ( S ) = 2

Let A be the event of getting a Head on tossing a coin i.e { Head }

∴ n( A ) = 1

Now,

$\textrm{Probability} =\frac{\textrm{outcomes for the experiment}}{\textrm{total number of outcomes}}$

Substituting the values we get

$P(A) = \frac{n(A)}{n(S)} \\\\P(A) = \frac{1}{2} \\\\P(A) = 0.5\\\\P(A) = 50\%$

The experamental probability that the coin lands on head is 50 %

5 0

3 years ago

Plss help it’s a test I’ll give 10 points

vodomira [7]

Answer:

Its the 3rd answer :)

<em>x = 26.94</em>

Step-by-step explanation:

<h2><em>This is because 25.5 + 1.44 = 26.94 :) (inverse operations ;))</em></h2>

<em />

4 0

3 years ago

Read 2 more answers

The world's biggest rubber band ball has a surface area of 27648. Using 3 as pi for both surface area and volume, estimate the v

jeyben [28]

We know that
surface area of sphere=4*pi*r²
r=√[surface area/(4*pi)]
for surface area=27648
r=√[27648/(4*3)]-------> r=√2304-----> r=48 units

volume of a sphere=(4/3)*pi*r³-----> (4/3)*3*48³---> 442638 units³

the answer is
<span>442368</span>

5 0

3 years ago

76 is 80% of what number

Shkiper50 [21]

Answer:

95

Step-by-step explanation:

6 0

3 years ago

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

3 years ago