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2 years ago

Simplify the expression:

Mathematics

2 answers:

Crank2 years ago

7 0

Answer:

3m + 3p + 3

Step-by-step explanation:

−2m + 4p + 5m −1p + 3

-2m + 5m + 4p - 1p + 3

3m + 3p + 3

Hope this helps!

larisa86 [58]2 years ago

4 0

Step-by-step explanation:

-2m + 4p + 5m - p + 3

-2m + 5m + 4p - p +3

+ 3m + 3p +3

3(m + p + 1 )

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Multiply (-1/3)(1/4)

ira [324]

Answer:

(-1/3 )(1/4)=(-1/12)

Step-by-step explanation:

(-1/3 )(1/4)

For fraction multiplication, multiply the numerators and then multiply the denominators to get

(-1/3 )(1/4)=(-1/12)

This fraction cannot be reduced.

Therefore:

(-1/3 )(1/4)=(-1/12)

6 0

3 years ago

Find the value(s) of k such that 4x² + kx + 4 = 0 has 1 rational solution

Blababa [14]

Answer:

If you mean only one rational solution, the answer is

$k_1 = 8, k_2 = -8$

If you mean at least 1 rational solution, the answer is

$k\in (-\infty, -8]\cup[8, \infty)$

Step-by-step explanation:

$4x^2 + kx + 4 = 0$

Let's calculate the discriminant.

$\Delta = b^2 - 4ac$

$\Delta = k^2 -4 \cdot 4 \cdot 4$

$\Delta = k^2 -64$

Now, remember that:

$\text{If } \Delta > 0 : \text{2 Real solutions}$

$\text{If } \Delta = 0 : \text{1 Real solution}$

$\text{If } \Delta < 0 : \text{No Real solution}$

Therefore, I will just consider the first two cases.

$k^2 - 64 > 0$

and

$k^2 -64 = 0$

$\boxed{\text{For } k^2 - 64 > 0}$

$k^2 > 64 \Longleftrightarrow k>\pm\sqrt{64} \Longleftrightarrow k\in (-\infty, -8)\cup(8, \infty)$

$\boxed{\text{For } k^2 - 64 = 0}$

$k^2 = 64 \Longleftrightarrow k=\pm\sqrt{64} \implies k_1 = 8, k_2 = -8$

7 0

3 years ago

Whats the solutions!?? look at the picture

gtnhenbr [62]

Answer:

3/x=y

Step-by-step explanation:

if not am sorry

6 0

3 years ago

Which point is on the line described by the equation below?

m_a_m_a [10]

Answer:

2,4

Step-by-step explanation:

3 0

3 years ago

Solve forj.<br> j + 20 > 17 orj + 17 < 5

lions [1.4K]

I’m confused my dude

7 0

3 years ago