Refer to the diagram shown below.
h = the height of the cliff.
d = the distance of the landing spot from the base of the cliff.
Assume that air resistance may be neglected, and g = 9.8 m/s².
The horizontal distance traveled in 2 seconds is
d = (1.8 m/s)*(2 s) = 3.6 m
The initial vertical velocity component is zero.
Therefore the vertical height traveled before landing on the water obeys the equation
h = (1/2)*(9.8 m/s²)*(2 s)² = 19.6 m
Answers:
The height of the cliff is 19.6 m
The distance of the landing spot from the base of the cliff is 3.6 m
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Answer:
1) FALSE
2) option A)
Step-by-step explanation:
1) the correct answer is FALSE
in traditional environment the raw material is delivered less frequent than lean environment.
2) the correct answer is option A)
preventive cost are those cost which are spent for the prevention of the good this cost is utilized when the project is under process and increasing preventive cost decreases defect of the end product.