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Eddi Din [679]
2 years ago
13

Angles of Triangles Practice Riddle

Mathematics
2 answers:
kherson [118]2 years ago
7 0
Would love to help but unsure what you are referring too
disa [49]2 years ago
4 0
Same you didn’t provide a question
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which graph represents a function with the domain of all real numbers greater than or equal to -7 and less than 2
Readme [11.4K]
Your answer should be D.......
5 0
3 years ago
Read 2 more answers
1. How many types of terms are there? ​
Sever21 [200]

Answer:

The are two types of terms.

One is Express terms: these are laid down by the parties themselves.

The second is Implied terms: these are read into the contract by the court on the basis of the nature of the agreement and the parties' apparent intentions, or on the basis of law on certain types of contract.

Hope this helps!

3 0
3 years ago
Triangle KLM is similar to Triangle RST.
fgiga [73]

Answer: true

Step-by-step explanation:

since the triangles are similar the sides are proportional

8 0
3 years ago
Read 2 more answers
ACD is a triangle and B is a point on AC. AB = 8cm and BC is 6cm. Angle BCD = 48° and angle BDC = 50°. (a) Find the length of BD
FromTheMoon [43]

Answer:

  • 5.8206 cm
  • 10.528 cm
  • 23.056 cm^2

Step-by-step explanation:

(a) The Law of Sines can be used to find BD.

  BD/sin(48°) = BD/sin(50°)

  BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm

__

(b) We can use the Law of Cosines to find AD.

  AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°

  AD^2 ≈ 110.841

  AD ≈ √110.841 ≈ 10.5281 . . . cm

__

(c) The area of ∆ABD can be found using the formula ...

  A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°

  A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2

_____

Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.

5 0
3 years ago
Simplify |-3-81<br> 0 A -11<br> O B. 5<br> O c. 5<br> O D. 11<br> Simplify |-3 - 8|
9966 [12]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
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