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Arlecino [84]
3 years ago
12

Consider the following pair of equations: y = x + 4 y = −5x − 2 Explain how you will solve the pair of equations by substitution

. Show all the steps and write the solution in (x, y) form.
Mathematics
2 answers:
timama [110]3 years ago
8 0

Answer:

(- 1, 3 )

Step-by-step explanation:

Given the 2 equations

y = x + 4 → (1)

y = - 5x - 2 → (2)

Substitute y = x + 4 into (2)

x + 4 = - 5x - 2 ( add 5x to both sides )

6x + 4 = - 2 ( subtract 4 from both sides )

6x = - 6 ( divide both sides by 6 )

x = - 1

Substitute x = - 1 into either of the 2 equations and evaluate for y

Substituting into (1)

y = - 1 + 4 = 3

solution is (- 1, 3 )

marissa [1.9K]3 years ago
6 0

Answer:

(-1, 3)

Step-by-step explanation:

to solve using substitution, you have to know the value of either x or y. in this example, they gave you the value of y already: y=x+4.

this means you can substitute the y for (x+4). if we substitute y for (x+4) in the equation y=-5x-2, we get this:

(x+4)=-5x-2

then solve for x

6x=-6

so x=-1

since we know the x value, we can solve for y

y=x+4

y=-1+4

y=3

so the final answer is (-1, 3)

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How do you solve for a and b showing your work
Mariulka [41]

Answer:

a) 4

b) \frac{1}{2} \sqrt{y^5}

Step-by-step explanation:

<u>PART A</u>

Simplify the expression by solving out the square roots.

\frac{\sqrt{16} \sqrt{p} }{\sqrt{p}} = \frac{4 \sqrt{p} }{\sqrt{p}}

You can cancel out the \sqrt{p} on the top and bottom.

So, a should be 4.

<u>PART B</u>

Solve out the square root. The square root is pretty much the 1/2 power, so you can divide the exponents by half.

\frac{\sqrt{y^{10}} }{\sqrt{4y^{5}} } = \frac{y^{5}}{2y^{\frac{5}{2}} }

You can subtract exponents to divide them. So the y variable becomes y^{5 - 5/2}, or y^{5/2}.

Then, the overall expression is \frac{1}{2} y^{\frac{5}{2} }, or you can turn that into \frac{1}{2} \sqrt{y^5}.

5 0
4 years ago
HELP THIS IF IS FOR MY NEXT YEAR CLASS LEVEL
Phoenix [80]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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I already tried to figure this out on my own but failed.
marissa [1.9K]

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6 0
3 years ago
In ∆DEF, the midpoint of the side opposite vertex D is M and the centroid is C. If DM is 6, what is DC and CM?
n200080 [17]

Answer:

DC = 4

CM = 2

Step-by-step explanation:

Remark

The centroid is located at the intersection point of all three medians of a triangle. The centroid is divides the median into a ratio of 2 to 1. The 1 is located closest to the intersection point of the median and the side opposite the vertex which is the starting point of the median.  

In this particular triangle  CM<DC

Givens

DC + CM = 6

CM <DC                  Labeled.

<em><u>Set up Proportion</u></em>

1:3 :: MC : (DC + CM)

1:3 :: MC : 6            

1/3 = MC/6              Cross Multiply

3*MC = 6                 Divide by 3

MC = 6/3                 Divide

Answer

MC = 2

DC = 6 -2 = 4

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