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Tatiana [17]
3 years ago
13

PLEASE Answer! I'll Give Brainliest And A Thanks For A GOOD Answer.

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer: Your welcome the answer is in the attached Image.

Step-by-step explanation: mark me brainliest.

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Walter wants computer software that cost $129. He has $57 saved. If he saves a maximum of $15 a week, the following inequality c
Lina20 [59]

In this question, it is given that

Walter wants computer software that cost $129. He has $57 saved.

he saves a maximum of $15 a week, the following inequality can be used to find how many weeks it will take Walter to save enough money to buy the software.

15x+57 \geq  129

And we have to solve this inequality for x.

First we subtract 57 to both sides. And on doing so , we will get

15x\geq  72

Dividing both sides by 15.

x \geq   4.8\

Correct option is A.

8 0
3 years ago
Explain why the graphing calculator cannot be used to solve or approximate solutions to all polynomial equations.
Lelu [443]
Let's put it this way:  If you plot a few non-x-intercept points and then draw a curvy line through them,you will not know if you got the x-intercepts even close to being correct. <span>The only way you can be sure of your x-intercepts is to set the quadratic equal to zero and solve. So its a matter of guessing from the pictures. Basicaly said, the calculator won't give you the exact result.</span>
4 0
3 years ago
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One of the models of spaceships in a museum is 7 inches long. The scale of a model spaceship is 1 inch to 16.5 feet. What is the
Alexandra [31]
The length of the spaceship would be 115.5 feet long.

7*16.5=115.5 feet

Hope this helps :)
3 0
3 years ago
Katherine purchased a pair of shoes on Boxing Day that originally cost $60 but was
Shkiper50 [21]
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3 years ago
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A bacteria population grows by 10% every 2 years. Presently, the population is 80 000 bacteria. Find the population 12 years ago
Sever21 [200]

In this problem

we have an exponential growth function of the form

y=a(1+r)^{\frac{t}{2}}

where

r=10%=0.10

Let

t=0 ---------> 12 years ago

so

Presently -------> t=12 years, y=80,000 bacteria

substitute

\begin{gathered} 80,000=a(1+0.10)^{\frac{12}{2}} \\ a=\frac{80,000}{1.10^6} \\  \\ a=45,158\text{ bacteria} \end{gathered}

therefore

<h2>The population 12 years ago was 45,158 bacteria</h2>
6 0
1 year ago
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