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Makovka662 [10]
2 years ago
7

Quadrilateral ABCD has vertices at A(2,-2), B(5,-2), C(8,-8), D(2,-5). What is the length of AC? (round to the nearest 10th)

Mathematics
1 answer:
morpeh [17]2 years ago
5 0

Answer:

The answer would be (6, -6)

I hope that helped! :)

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Please help me with this quick :))))))))
vredina [299]

Answer:

129.3 in²

Step-by-step explanation:

The shaded segment is calculated as

area of sector ABC - area of triangle ABC

area of sector = area of circle × fraction of circle

A = πr² × \frac{60}{360}

   = π × 18² × \frac{1}{6}

   = 324π × \frac{1}{6} = 54π in²

area of Δ ABC = \frac{1}{2} × 18 × 18 × sin60°  ≈ 40.30 in²

Then

shaded area = 54π - 40.30 ≈ 129.3 in² ( to the nearest tenth )

6 0
3 years ago
What is the length of BC? Round to the nearest tenth
Degger [83]

Answer:

9.9

use the special triangle formula or use cosine to find BC

7 0
3 years ago
The tables below show the values of f (x) and g (x) for different values of x:
dimaraw [331]
<span>2(3)× = 3×+1 is equal when f(x) = g(x).
f(x) is equal to g(x) when x = 0.
Therefore, the solution to the equation </span><span>2(3)×=3×+1 is x = 0.</span>
4 0
3 years ago
PLEASE HELP I need the answer for this ASAP pleaseeeee
True [87]

Answer:

13

Step-by-step explanation:

f(x) = 5 \sqrt{x}  + 8 \\ f(1) = 5 \sqrt{1}  + 8 \\13

Hope this helps..

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Diagnostic Test
Semmy [17]

Answer:

B.

Step-by-step explanation:

5 0
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