If x>4, then the quantity x-3 inside the absolute value symbol is already positive. So, in this case, |x-3| => x-3, and x-3 is all you need to write.
1,6,11,16,21,26 is what you would get if you add 5.
Answer:
56
Step-by-step explanation:
447/8
56
well actually
55.875
I just rounded it up
Answer:
1<x≤3
Step-by-step explanation:
Answer:
yes that is right
Step-by-step explanation:
