Well, the sum of all internal angles in a triangle, isosceles or whatever else, is always 180°, so the sum of all those three folks, will be 180 then

so.. hmmm let's say the smallest angle is "a" units

twice that is, 2*a, or 2a
25 larger than that? is well 2a + 25

so... the other two twin angles, are 2a+25 each

thus a + (2a + 25) + (2a + 25) = 180

solve for "a" to find the smalles one

what about the twins? well, each is 2a + 25

5 0

3 years ago

Find the real solutions, if any, of the following equation. Use the quadratic formula. x^2 square root 2x -5 =0

JulijaS [17]

Answer:

x = 0 or x = 5/2

Step-by-step explanation:

Solve for x over the real numbers:

x^2 sqrt(2 x - 5) = 0

Split into two equations:

x^2 = 0 or sqrt(2 x - 5) = 0

Take the square root of both sides:

x = 0 or sqrt(2 x - 5) = 0

Square both sides:

x = 0 or 2 x - 5 = 0

Add 5 to both sides:

x = 0 or 2 x = 5

Divide both sides by 2:

Answer: x = 0 or x = 5/2

3 0

3 years ago