3 years ago

Is this the right answer....???????

1 answer:

5 0

Answer:

yes

Step-by-step explanation:

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wel

A^2+b^2=c^2 so 4(4) +3(3) is 16+9= 25 and the square root of that is 5.

7 0

2 years ago

Shalnov [3]

This is what i got in the caculator 6400 if not im so so sory

8 0

2 years ago

Mekhanik [1.2K]

$\frac{ - 3}{8} \times \frac{8}{15} \\ \\ = \frac{ \cancel{- 3}}{ \cancel8} \times \frac{ \cancel8}{ \cancel{15}} \\ \\ = - \frac{1}{5}$

Hope This Helps ~

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1 year ago

max2010maxim [7]

The value of the expression $\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$ is $2xy\sqrt{y} + 2xy^2\sqrt{x}$

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

$\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$

Expand the radicands

$\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y$

Evaluate the square roots

$xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y$

Add the like terms

$2xy\sqrt{y} + 2xy^2\sqrt{x}$

Hence, the value of the expression $\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$ is $2xy\sqrt{y} + 2xy^2\sqrt{x}$