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Eddi Din [679]
3 years ago
11

Three baseball players are playing catch. Clayton is directly south of Shawn and directly west

Mathematics
1 answer:
seropon [69]3 years ago
8 0
Use Pythagorean Theorem.
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Let f be a function of two variables that has continuous partial derivatives and consider the points
Sergeu [11.5K]

Answer:

The directional derivative of f at A in the direction of \vec{u} AD is 7.

Step-by-step explanation:

Step 1:

Directional of a function f in direction of the unit vector \vec{u}=(a,b) is denoted by D\vec{u}f(x,y),

D\vec{u}f(x,y)=f_{x}\left ( x ,y\right ).a+f_{y}(x,y).b.

Now the given points are

A(8,9),B(10,9),C(8,10) and D(11,13),

Step 2:

The vectors are given as

AB = (10-8, 9-9),the direction is

\vec{u}_{AB} = \frac{AB}{\left \| AB \right \|}=(1,0)

AC=(8-8,10-9), the direction is

\vec{u}_{AC} = \frac{AC}{\left \| AC \right \|}=(0,1)

AC=(11-8,13-9), the direction is

\vec{u}_{AD} = \frac{AD}{\left \| AD \right \|}=\left (\frac{3}{5},\frac{4}{5}  \right )

Step 3:

The given directional derivative of f at A \vec{u}_{AB} is 9,

D\vec{u}_{AB}f=f_{x} \cdot 1 + f_{y}\cdot 0\\f_{x} =9

The given directional derivative of f at A \vec{u}_{AC} is 2,

D\vec{u}_{AB}f=f_{x} \cdot 0 + f_{y}\cdot 1\\f_{y} =2

The given directional derivative of f at A \vec{u}_{AD} is

D\vec{u}_{AD}f=f_{x} \cdot \frac{3}{5} + f_{y}\cdot \frac{4}{5}

D\vec{u}_{AD}f=9 \cdot \frac{3}{5} + 2\cdot \frac{4}{5}

D\vec{u}_{AD}f= \frac{27+8}{5} =7

The directional derivative of f at A in the direction of  \vec{u}_{AD} is  7.

3 0
3 years ago
What is the simplified form of the expression 0.3 (4x - 4y)?
Agata [3.3K]

Answer:

1.2x-1.2y

Step-by-step explanation:

8 0
3 years ago
What is the answer for this question
dolphi86 [110]
Answer: 35

Explanation: They originally paid 75$ for the uniforms. We know this because 3000/40 = 75. So the difference would be 75-40, which is 35...

So the answer is 35
6 0
4 years ago
I need help please answer with explantation
ExtremeBDS [4]

Answer:

what is it about i mite help

Step-by-step explanation:

okay!

3 0
4 years ago
The equation of line AB is (y-3) = 5 (x - 4). What is the slope of a line perpendicular to line AB?
Nastasia [14]
Y - 3 = 5(x - 4)
y - 3 = 5x - 20
y = 5x - 20 + 3 = 5x - 17
=> slope = 5

For perpendicular line, m2 = -1/m1 = -1/5
5 0
3 years ago
Read 2 more answers
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