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mote1985 [20]
4 years ago
13

A plant 3 in. tall grows an average of 0.5 in. each month. Which equation models the flower’s height h after x months

Mathematics
1 answer:
Ymorist [56]4 years ago
6 0
3 divided by 0.5 = x months and this equals 6 months

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Using scientific notation, what is the solution to (2.82 * 104) * (3.1 * 103)?
MArishka [77]

Answer: Choice A) 8.742 * 10^7

=====================================

Work Shown:

(a * 10^b) \times (c * 10^d) = a*c*10^{b+d}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 2.82*3.1*10^{4+3}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 8.742*10^{7}\\\\

Extra info:

8.742 * 10^7 = 87,420,000

which is a little over 87.4 million

6 0
3 years ago
The slope of the line below is 2. Which of the following is the the point-slope form of the line?
Jobisdone [24]

Answer:  y + 1 = 2 (x -1)

Step-by-step explanation:

Point slope form is:

y - y1 = m (x - x1)

Point on the line is (1, -1) and slope is 2

m = 2

y1 = -1

x1 = 1

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5 0
3 years ago
Which type of business would tend to use bank loans?
trasher [3.6K]
All business due this; probably locally own. 
4 0
3 years ago
Find the lateral area of the regular pyramid<br><br> L.A. =
Arisa [49]

Answer:

FOR REGULAR PYRAMID with those dimension.

L.A = 96

FOR HEXAGONAL PYRAMID with those dimension

L.A = 171.71

Step-by-step explanation:

Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.

Hence I solved for both:

FOR REGULAR PYRAMID

Lateral Area (L.A) = 1/2* p * l

Where p = Perimeter of base

P = 4s

P = 4 * 6

P = 24cm

l = slanted height

l = 8cm

L.A = 1/2 * 24 * 8

L.A = 1/2 ( 192)

L.A = 96cm ^ 2

FOR AN HEXAGONAL PYRAMID

Lateral Area = 3a √ h^2 + (3a^2) / 4

Where:

a = Base Edge = 6

h = Height = 8

L.A = 3*6 √ 8^2 + ( 3*6^2) / 4

L.A = 18 √ 64 + ( 3 * 36) / 4

L.A = 18 √ 64 + 108/4

L.A = 18 √ 64+27

L.A = 18 √ 91

L.A = 18 * 9.539

L.A = 171.71

8 0
3 years ago
Thanks for the help...........
Natali [406]

Answer:

Option C

Step-by-step explanation:

It was rotated to the right

6 0
3 years ago
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