Ask question

Ask question

All categories

3 years ago

13

Divide the number of meters by to find the number of laps

1 answer:

Igoryamba3 years ago

3 0

Answer:

Solution for Divide the number of meters by to find the number of laps. Runners 3 4 Number of Laps 4. 8 12 Number of Meters 1600 3200 4800 6400 de the…

Step-by-step explanation:

You might be interested in

Express in exponential form.<br><br> x = logby

Lunna [17]

X = log (base b) y
The base of the log becomes the base of the exponent.
The x and y switch.
b^x = y

6 0

4 years ago

Read 2 more answers

Carlos has a string that is 24 inches long he wants to divide it into three equal parts write an equation to find how long each

katrin2010 [14]

Answer: 24 ÷ 3

Step-by-step explanation: You do 24÷3 because he has a string that is 24 inches long and if he wanted to divide it into 3 equal pieces . You would get 8 inches long for each piece (8x3) or (3x8)

4 0

3 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Which regression line properly describes the data relationship in the scatterplot?

TEA [102]

Answer:C

Step-by-step explanation:

Bc there's 3 does below and 3 dots above

6 0

3 years ago

Read 2 more answers

Please help ASAP thank you!!!!

mart [117]

Answer:

41. f⁻¹(x) = -9x + 4

43. m⁻¹(x) = ∛(x-2)/4

Step-by-step explanation:

41. y = (4-x)/9

swap x and y: x = (4-y)/9

solve y: 9x = 4-y

y = -9x + 4

45. y = 4x³+2

x = 4y³+2

4y³ = x-2

y³ = (x-2)/4

y = ∛(x-2)/4

Let you do 42 and 46 by yourself

5 0

3 years ago