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astraxan [27]
3 years ago
13

Find the roots of the following polynomial equations: 1. y = 2x2 + 3x - 5​

Mathematics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

Step-by-step explanation:

y=2x^2+3x+5\\

Using the quadratic formula:

\frac{-3+-\sqrt{9-4(2)(5)}}{2(2)} = \frac{-3+-\sqrt{-31}}{4}

Since the discriminant is negative, -31, there are no real roots

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Vedmedyk [2.9K]

48 ÷ 200 = 0.24

0.24 × 25 = 6

She will pay $6

4 0
3 years ago
What is the greatest common factor of 16,32, and 44?
liubo4ka [24]
The greatest common factor of the three numbers is 4
4 0
3 years ago
You jog 2 kilometers in 12 minutes. Your friend jogs 3 kilometers in 16.5 minutes. Who jogs faster? You jog faster. Your friend
Darya [45]

Answer:

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Step-by-step explanation:

Speed = Distance(km)/Time(hours)

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend's will finish a 5km race at a speed of 18.18 km/hr

Your speed is :

You jog 2 kilometers in 12 minutes.

Convert 12 minutes to hours

60 minutes = 1 hour

12 minutes = x

x = 12/60

x = 1/5 hour

Your speed is calculated as:

2km/1/5hour

= 2 km ÷ 1/5 hour

= 2 × 5

= 10 km/hr

Your friend's speed is calculated as:

Your friend jogs 3 kilometers in 16.5 minutes.

Convert 16.5 minutes to hours

60 minutes = 1 hour

16.5 minutes = x

x = 16.5/60

x = 0.275 hour

Your speed is calculated as:

3km/0.275 hour

= 10.909090909 km/hr

Approximately = 10.91km/hr

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend jogs faster, hence:

3 km = 10.91 km/hr

5km = x

x = 5 × 10.91/3

x = 18.183333333 km/hr

Your friend's will finish a 5km race at a speed of 18.18 km/hr

4 0
3 years ago
vDetermine if a Poisson experiment is described, and select the best answer: Suppose we knew that the average number of typos in
goldenfox [79]

Answer:

probability that a randomly selected page that contains only text will contain no typos that is

P(x=0) = e^{-0.08} = 0.923

Step-by-step explanation:

<u>Poisson distribution</u>:-

Explanation of the Poisson distribution :-

The Poisson distribution can be derived as a limiting case of the binomial

distribution under the conditions that

i) p is very small

ii) n is very large

ii) λ = np (say finite

The probability of 'r' successes = \frac{e^{-\alpha }\alpha^r  }{r!}

Given the average number of typos ∝ = 0.08 per page.

probability that a randomly selected page that contains only text will contain no typos that is = p(x=0) = \frac{e^{-0.08 }\(-0.08)^0  }{0!}

After calculation P(x=0) = e^{-0.08} = 0.923

probability that a randomly selected page that contains only text will contain no typos =0.923

5 0
3 years ago
X -(2x- 3x-4/7) = 4x -27/3 -3​
RUDIKE [14]
RHS
=4x-27/0
=not defined=0

LHS
=x-2x+3x+4/7=2x+4/7=(14x+4)/7= 14x+4.

14x=-4

x=-4/14

X=-2/7
7 0
3 years ago
Read 2 more answers
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