PLEASE SHOW WORK

Type the correct answer in the box use/ for the fraction bar

Zarrin [17]

Answer:

see explanation

Step-by-step explanation:

given the 2 equations

y = x² - 2x - 19 → (1)

y + 4x = 5 → (2)

substitute y = x² - 2x - 19 into (2)

x² - 2x - 19 + 4x = 5 ( subtract 5 from both sides )

x² + 2x - 24 = 0 ← in standard form

(x + 6)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x + 6 = 0 ⇒ x = - 6

x - 4 = 0 ⇒ x = 4

substitute each value of x into (1) for corresponding y- coordinate

x = - 6 : y = (- 6)² - 2(- 6) - 19 = 36 + 12 - 19 = 29 ⇒ (- 6, 29)

x = 4 : y = 4² - 2(4) - 19 = 16 - 8 - 19 = - 11 ⇒ (4, - 11)

the solutions are (- 6, 29), (4, - 11)

6 0

2 years ago

14 out of the 25 students passed the quiz. What percent of students passed the quiz ?

Mnenie [13.5K]

Answer:

56

Step-by-step explanation:

A fraction consists of two numbers and a fraction bar:

14/25

The number above the bar is the numerator: 14

The number below the bar is the denominator: 25

Divide the numerator by the denominator to get fraction's value:

Val = 14 ÷ 25

Hoped it helped

7 0

2 years ago

Select the correct order for the following numbers

Andru [333]

Answer:

cdab

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the radius of a circumference 56.5

Bas_tet [7]

8.992254284692088 is the radius I believe

7 0

3 years ago

Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f

vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

$f(x)=ax^3+bx^2+cx+d$

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

$y = x^3 - x$

Equate y to 0

$x^3 - x = 0$

Expand

$x(x^2 - 1) = 0$

Express $x^2 - 1$ as difference of two squares

$x(x - 1)(x +1 ) = 0$

x = 0 or 1 or -1

For 2 x intercepts

$y = x^3 - x$

$y =(x-5)^2)(x+7)$

Equate y to 0

$(x-5)^2(x+7) = 0$

Expand

$(x-5)(x-5)(x+7) = 0$

x= 5 or x = -7

For 1 x intercept

$y = x^3$

Equate y to 0

$x^3 = 0$

Take cube roots of both sides

$x = 0$

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

$y = x^2 + x + 17$

The above function has no x intercept.

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

$y = x^2- 6x + 9$

Equate y to 0

$x^2- 6x + 9 = 0$

Expand

$x^2 - 3x - 3x + 9 = 0$

$(x - 3)(x-3) = 0$

$x = 3$

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0

2 years ago