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IrinaK [193]
2 years ago
13

Pls help me solve this please I will give 70 points please help

Mathematics
1 answer:
Mashutka [201]2 years ago
5 0

Answer:

Fraction Form: \frac{2187}{4000000}

Decimal Form: 0.000547

Step-by-step explanation:

=\frac{5}{256} * \frac{3}{5}^1^2 / \frac{3}{5}^5

\frac{3}{5}^1^2/\frac{3}{5}^5=\frac{2187}{78125}

=\frac{5}{256}*\frac{2187}{78125}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

\frac{5*2187}{256*78125}

\mathrm{Factor\:the\:number:\:}\:78125=5\cdot \:15625

=\frac{5*2187}{256*5*15625}

\mathrm{Cancel\:the\:common\:factor:}\:5

=\frac{2187}{256*15625}

\mathrm{Multiply\:the\:numbers:}\:256\cdot \:15625=4000000

\frac{2187}{4000000}

[RevyBreeze]

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We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let p_1 = <u><em>percentage of employed workers who have registered to vote.</em></u>

p_2 = <u><em>percentage of unemployed workers who have registered to vote.</em></u>

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, H_A : p_1>p_2     {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here <u>Two-sample z test for proportions;</u>

                          T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of employed workers who have registered to vote = \frac{287}{513} = 0.56

\hat p_2 = sample proportion of unemployed workers who have registered to vote = \frac{280}{604} = 0.46

n_1 = sample of employed persons = 513

n_2 = sample of unemployed persons = 604

So, <u><em>the test statistics</em></u>  =  \frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }

                                       =  3.349

The value of z test statistics is 3.349.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

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