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Colt1911 [192]
2 years ago
15

Hi ill give points answer me now bye

Mathematics
2 answers:
melomori [17]2 years ago
6 0
Bettttttttttttttttttttttttttttttttttttttttttt
Usimov [2.4K]2 years ago
5 0
Can you pls brainlest me I need it so much
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2 po
Lyrx [107]

Answer:

Step-by-step explanation:

Girls:Total number of people

89:235

89:47

8 0
3 years ago
Given tanø=(4/3) and 0<ø<(3pi/2) find cos20
ycow [4]

Answer:

Step-by-step explanation:

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here is an solution

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3 years ago
Which multiplication expression can be used to check this division problem:
borishaifa [10]

Answer:

° 3/2 × 4/15

Step-by-step explanation:

for checking a division problem use the product and one of the fractions to multiply. if the answer matches the other fraction then your division is correct.

6 0
3 years ago
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A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents di
cupoosta [38]

Answer:

The probability value is almost equal to 0. Implying that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents died in the three-month period following their birthdays (123).

The probability (p) of anyone dying in any quarter if people die randomly during the year is simply 0.25.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 747 and p = 0.25.

But the sample selected is too large and the probability of success is small.

So a Normal approximation to binomial can be applied to approximate the distribution of <em>p</em> if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=747\times 0.25=186.75>10\\n(1-p)=747\times (1-0.46)=560.25>10

Thus, a Normal approximation to binomial can be applied.

So,  p\sim N(\hat p,\ \frac{\hat p(1-\hat p)}{n}).

Compute the probability that 46% or more would die in that particular interval if deaths occurred randomly throughout the year as follows:

P (p\geq 0.46)=P(\frac{p-\hat p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}>\frac{0.46-0.25}{\sqrt{\frac{0.25(1-0.25)}{747}}})

                   =P(Z>13.25)\\=1-P(Z

 *Use a <em>z</em> table for the probability.

The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

3 0
3 years ago
If 1,050 females participated in the study, how many females prefer purple?
amm1812
1050 females
23% prefer purple

1050 : 100 *23 =
241.5 females prefer purple

6 0
3 years ago
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