Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
It’s the area of the outside or something
If you know the slope of a linear relationship as well as one of the points, you can determine if the relationship is proportional if the value of y is equal to the value of the slope times the x value.
<h3>When is a relationship proportional?</h3>
The linear relationship of x and y is said to be proportional if:
y = slope × x
This means that the value of y is directly related to the value of x such that when x is increased by a certain value, you get y.
If this condition is not satisfied then the relationship is not proportional.
The linear relationship above is therefore proportional if the value of y in the point is the same as x when multiplied by the slope.
Find out more on proportional relationships at brainly.com/question/3383226
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The closest one is 5 to the power of 1 over 3.
sq rt of 3 = 1.732
sq rt of 5 = 2.236
5^1/3 = 1.667
5^1/6 = 0.833
5^2/3 = 8.333
5^3/2 = 62.5
Answer:
I think A
Step-by-step explanation:
