$\sec( \alpha ) = \frac{1}{ \cos( \alpha ) } \\ \\ \sec( \alpha ) = \frac{1}{ \frac{ad}{hip} } \\ \\ \sec( \alpha ) = \frac{hip}{ad} \\ \\ \sec( \alpha ) = \frac{41}{40}$

3 0

3 years ago

Read 2 more answers

6x^2-16x+5=0 A. 8/3 B. -3/8 C. 5/6 D. -5/16

stealth61 [152]

The answer to the question is a

6 0

3 years ago

How do you do part B of this question? Please help!!

posledela

All i know is that the equation of a straight line is y=mx+c .......where m= gradient and c= the y intercept

3 0

3 years ago

Write an equation for each condition listed.

Svetlanka [38]

Look for the y-intercept
since we know the slope is 3 we just going to plug in
-5=3(1)+y
-5-3=y
so the y-intercept is 8 now you can find the equation
y=3x-8

6 0

3 years ago