Question

What is the value of sec in the triangle below? 41 ft 9 ft 40 ft

Answer 1

Answer:

C 41/40 I hope  this helps!

Answer 2

Answer:

C

Step-by-step explanation:

$\sec( \alpha ) = \frac{1}{ \cos( \alpha ) } \\ \\ \sec( \alpha ) = \frac{1}{ \frac{ad}{hip} } \\ \\ \sec( \alpha ) = \frac{hip}{ad} \\ \\ \sec( \alpha ) = \frac{41}{40}$