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kondor19780726 [428]
2 years ago
15

I have to take this high school class and its on the face feautures were suppsoped to ask random people so just looking at me wh

at do you see dont say ugly or pretty looking at me what can you tell about me without even knowing me Thanks for the help!

Mathematics
1 answer:
zzz [600]2 years ago
3 0

Answer:

you don't know how to take proper pics..

you looks a little boring..

and maybe intelligent..

and can't tell more since it's not very clear

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Employment data at a large company reveal that 75% of the workers are​ married, 42​% are college​ graduates, and half of the col
galina1969 [7]

Answer:

a. P=0.04

b. P=0.54

c. P=0.96

Step-by-step explanation:

If half of the college graduates are married, then we have:

- 21% are college graduates and married.

- 21% are college graduates and not married.

If 75% of the workers are married, and 21% of the workers are college graduates and married, then (75%-21%)=54% of the workers are not college graduates that are married.

If 25% of the workers are married, and 21% of the workers are college graduates and not married, then (25%-21%)=4% of the workers are not college graduates that are not married.

a) P=0.04 (explanation above)

b) P=0.54

c) In this case, the probability is the complement of point "a". Then we can calculate it by substracting the probability of not being married and not being a college graduate.

P=1-0.04=0.96

8 0
3 years ago
As x approaches 4, the value of 4x + 3 approaches<br> Gri
gogolik [260]

Answer:

19

Step-by-step explanation:

4 \times x + 3 = 4 \times 4 + 3 = 16 + 3 = 19

3 0
3 years ago
Is 0.3 equal to 1/3, or 3/10?
Stolb23 [73]

Answer: 3/10

3/10 = 0.3


8 0
3 years ago
Read 2 more answers
(5x^5) - (80x^3)<br> factoring
elena55 [62]

Answer:

Factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

(5x^5) - (80x^3)\\=5x^3(x^2-16)

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)

So, factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

4 0
3 years ago
Mark has some candy bars that he wants to give away. He is going to give each person 28 of a bar, and he has 4 bars to give away
Snowcat [4.5K]

Answer:

7 people

Step-by-step explanation:

6 0
2 years ago
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