128/9223)8”,/2881/38 así
12–8-!2
we conclude that the center of the circle is the point (-5, 0).
<h3>How to find the center of the circle equation?</h3>
The equation of a circle with a center (a, b) and a radius R is given by:
![(x - a)^2 + (y - b)^2 = R^2](https://tex.z-dn.net/?f=%28x%20-%20a%29%5E2%20%2B%20%28y%20-%20b%29%5E2%20%3D%20R%5E2)
Here we are given the equation:
![x^2 + y^2 + 10x - 1 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%20y%5E2%20%2B%2010x%20-%201%20%3D%200)
Completing squares, we get:
![x^2 + 10x + y^2 = 1](https://tex.z-dn.net/?f=x%5E2%20%2B%2010x%20%2B%20y%5E2%20%3D%201)
Now we can add and subtract 25 to get:
![x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26](https://tex.z-dn.net/?f=x%5E2%20%2B%2010x%20%2B%2025%20-%2025%20%2B%20y%5E2%20%3D%201%5C%5C%5C%5C%28x%20%2B%205%29%5E2%20-25%20%2B%20y%5E2%20%3D%201%5C%5C%5C%5C%28x%20%2B%205%29%5E2%20%2B%20%28y%20-%200%29%5E2%20%3D%2026)
Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).
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The area of the shaded triangle formed as the result of the overlap is = 62.35 inches ²
<h3>Calculation of the equilateral triangle</h3>
After folding the rectangle with length of 12 inches and width of 18 inches, an equilateral triangle was formed.
An equilateral triangle is a type of triangle where by all the three sides are equal.
To determine the value of one of the sides, CB or CD is used because the folding didn't affect these sides.
Using the formula for the area of an equilateral triangle,
A = √¾ a²
a= 12 inches
A = √¾ ×12²
A = 62.35 inches ²
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Answer:the answer is B
Step-by-step explanation:Bisect each of the angles with vertices at their houses
The area of the arrow it's 660 cm.