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Karolina [17]
3 years ago
6

Employment data at a large company reveal that 75% of the workers are​ married, 42​% are college​ graduates, and half of the col

lege grads are married. Complete parts a through c below.
a) What's the probability that a randomly chosen worker is neither married nor a college​ graduate? ​(Type an integer or a decimal. Do not​ round.)

b) What's the probability that a randomly chosen worker is married but not a college​ graduate? ​(Type an integer or a decimal. Do not​ round.) ​

c) What's the probability that a randomly chosen worker is married or a college​ graduate? ​(Type an integer or a decimal. Do not​ round.)
Mathematics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

a. P=0.04

b. P=0.54

c. P=0.96

Step-by-step explanation:

If half of the college graduates are married, then we have:

- 21% are college graduates and married.

- 21% are college graduates and not married.

If 75% of the workers are married, and 21% of the workers are college graduates and married, then (75%-21%)=54% of the workers are not college graduates that are married.

If 25% of the workers are married, and 21% of the workers are college graduates and not married, then (25%-21%)=4% of the workers are not college graduates that are not married.

a) P=0.04 (explanation above)

b) P=0.54

c) In this case, the probability is the complement of point "a". Then we can calculate it by substracting the probability of not being married and not being a college graduate.

P=1-0.04=0.96

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Furkat [3]

The speed of light is 300,000 kilometers per hour. hence option c is correct.

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<h2>\frac{6}{25}</h2>

Step-by-step explanation:

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7 0
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8. A company makes electronic components for TV's. 95% pass final inspection (and 5% fail and need to be fixed). 120 components
Taya2010 [7]

Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.

For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

V(X) = np(1 - p)

In this problem:

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The variance is given by:

V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7

The variance of the number that pass inspection in one day is 5.7.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

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stira [4]

Answer: 34

Step-by-step explanation:

3 0
3 years ago
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