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Karolina [17]
3 years ago
6

Employment data at a large company reveal that 75% of the workers are​ married, 42​% are college​ graduates, and half of the col

lege grads are married. Complete parts a through c below.
a) What's the probability that a randomly chosen worker is neither married nor a college​ graduate? ​(Type an integer or a decimal. Do not​ round.)

b) What's the probability that a randomly chosen worker is married but not a college​ graduate? ​(Type an integer or a decimal. Do not​ round.) ​

c) What's the probability that a randomly chosen worker is married or a college​ graduate? ​(Type an integer or a decimal. Do not​ round.)
Mathematics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

a. P=0.04

b. P=0.54

c. P=0.96

Step-by-step explanation:

If half of the college graduates are married, then we have:

- 21% are college graduates and married.

- 21% are college graduates and not married.

If 75% of the workers are married, and 21% of the workers are college graduates and married, then (75%-21%)=54% of the workers are not college graduates that are married.

If 25% of the workers are married, and 21% of the workers are college graduates and not married, then (25%-21%)=4% of the workers are not college graduates that are not married.

a) P=0.04 (explanation above)

b) P=0.54

c) In this case, the probability is the complement of point "a". Then we can calculate it by substracting the probability of not being married and not being a college graduate.

P=1-0.04=0.96

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Answer:

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Step-by-step explanation

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3 years ago
en una balansa de platillos esta equilibrada, en uno de los platillos hay una piedra, una pesa de un noveno kilogramos y la otra
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Se escribe una equacion y se resolve.

Vamos a usar x para representar el peso de la piedra.

En en platillo que tiene la piedra, el peso total es: x + 1/9 + 2/3

En el otro platillo: 1/2 + 1/3

La balanza esta equilibrada por eso los pesos en los platillos son iguales.

x + 1/9 + 2/3 = 1/2 + 1/3

x + 2/18 + 12/18 = 9/18 + 6/18

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A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?
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The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

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Now, for 20g weight the maximum number of weights needed will be 1 that is :

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Now, for 10g weight the maximum number of weights needed will be 1 that is :

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Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.

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