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Karolina [17]
3 years ago
6

Employment data at a large company reveal that 75% of the workers are​ married, 42​% are college​ graduates, and half of the col

lege grads are married. Complete parts a through c below.
a) What's the probability that a randomly chosen worker is neither married nor a college​ graduate? ​(Type an integer or a decimal. Do not​ round.)

b) What's the probability that a randomly chosen worker is married but not a college​ graduate? ​(Type an integer or a decimal. Do not​ round.) ​

c) What's the probability that a randomly chosen worker is married or a college​ graduate? ​(Type an integer or a decimal. Do not​ round.)
Mathematics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

a. P=0.04

b. P=0.54

c. P=0.96

Step-by-step explanation:

If half of the college graduates are married, then we have:

- 21% are college graduates and married.

- 21% are college graduates and not married.

If 75% of the workers are married, and 21% of the workers are college graduates and married, then (75%-21%)=54% of the workers are not college graduates that are married.

If 25% of the workers are married, and 21% of the workers are college graduates and not married, then (25%-21%)=4% of the workers are not college graduates that are not married.

a) P=0.04 (explanation above)

b) P=0.54

c) In this case, the probability is the complement of point "a". Then we can calculate it by substracting the probability of not being married and not being a college graduate.

P=1-0.04=0.96

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The mean of the values in a data set is c. If each of the values in the data set were multiplied by 6, what would be the mean of
oksian1 [2.3K]

Answer:

Mean of the data would be 6c

Step-by-step explanation:

<u>Rule to Remember:</u> Whenever each term of the data is multiplied by the same number, the new mean is previous mean multiplied by that number.

In this case, original value of mean was c. Each value of the data is multiplied with 6 so a result the new mean would be 6 times the original mean i.e. 6c

Let us consider that original values in the data set are x, y and z. Their mean would be:

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If each value of the data is multiplied with 6, the new values would be 6x, 6y and 6z. The mean in this case will be:

Mean=\frac{6x+6y+6z}{3}\\Mean=\frac{6(x+y+z)}{3}\\Mean=6\times\frac{x+y+z}{3}\\Mean=6c

We can see from above that the new mean is 6 multiplied to the original mean.

Therefore, the answer to this question is 6c.

7 0
3 years ago
Question 2 Two trains leave the station at the same time, one heading west and the other east. The westbound train travels at 95
lianna [129]

Answer:

it will take 1.4 hours for the two trains to be 294 miles apart

Step-by-step explanation:

Let t be the time taken for each train

The westbound train travels at 95 miles per hour.

Speed of westbound train = 95

time = t

Distance = speed * time = 95 t

The eastbound train travels at 115 miles per hour

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So we add the distance of both trains and set it equal to 294

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1,35,36,37,37,38 mean median mode
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Answer:

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So, 1+35+36+37+37+38= 184. Then, divide it 184/6= 30.6. The mode is the number that occurs the most in that set of numbers. In this case, it would be 37. The median is basically the number in the middle when the set of numbers is ordered from least to greatest. 1,35,36,37,37,38 (here's a hint: cross it off on each side) If there is no obvious middle number, in this case because we have an even set of numbers, we can calculate the median by taking the mean of the 2 middlemost terms and: 36, 37. 

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4 0
3 years ago
Read 2 more answers
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alexira [117]

Answer:

D

Step-by-step explanation:

Our inequality is 8 < x < 10, where x is our number.

Since the problem doesn't specify whether the number x is an integer or not, we can assume that x can be either a decimal or a whole number. That means that we want any decimal number or whole number between 8 and 10. The only whole number is 9, but there are infinitely many decimal solutions. For example, we could have 8.001, 8.0001, 8.00001, etc.

Thus the answer is D.

Hope this helps!

4 0
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