Answer:

Explanation:
We have to remember the <u>molarity equation</u>:

So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the <u>conversion</u>:

Now we can calculate the moles. For this we have to calculate the <u>molar mass</u>:
O: 16 g/mol
H: 1 g/mol
C: 12 g/mol

With the molar mass value we can <u>calculate the number of moles</u>:

Finally, we can <u>calculate the molarity</u>:

I hope it helps!
Answer:
The molarity of the diluted HCl solution: <u>M₂ = 0.045 M</u>
Explanation:
To find- the molarity of the diluted HCl solution (M₂)
Given- <u>For original HCl solution</u>-
Molarity: M₁ = 1.5 M, Volume: V₁ = 60.0 ml = 0.06 L (∵ 1L = 1000 mL)
Then this original solution is diluted to a volume of 2 L
Thus <u>for the diluted HCl solution</u>-
The Volume of the diluted HCl solution: V₂ = 2 L
<u>So the Molarity of the diluted HCl solution (M₂) can be calculated by the </u><u><em>dilution equation:</em></u>



<u>Therefore, the molarity of the diluted HCl solution: M₂ = 0.045 M</u>
Let us assume that the oxygen behaves as an ideal gas such that we can use the ideal gas equation to solve for the number of moles of O2.
PV = nRT ; n = PV/RT
Substituting the known values,
n = (0.930 atm)(93/1000 L) / (0.0821 L.atm/mol.K)(10 + 273.15K)
n = 3.72 x 10^-3 mols
At STP, the volume of each mol of gas is equal to 22.4 L.
volume = (3.73 x 10^-3 mols) x (22.4 L/1 mol)
volume = 0.0833 L or 83.34 mL
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It would be (1) magnesium.
hope this helps :D