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Ivan
4 years ago
11

93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0 C.what would be the volume of this dry gas at STP

Chemistry
1 answer:
ExtremeBDS [4]4 years ago
5 0
Let us assume that the oxygen behaves as an ideal gas such that we can use the ideal gas equation to solve for the number of moles of O2.
                       PV = nRT   ; n = PV/RT
Substituting the known values,
               n = (0.930 atm)(93/1000 L) / (0.0821 L.atm/mol.K)(10 + 273.15K)
                             n = 3.72 x 10^-3 mols
At STP, the volume of each mol of gas is equal to 22.4 L.
                          volume = (3.73 x 10^-3 mols) x (22.4 L/1 mol)
                           volume = 0.0833 L or 83.34 mL
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8 0
4 years ago
3. How many moles of silver is 8.46x1024 atoms of<br> silver?
ioda

Answer:

<h2>14.05 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.46 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 14.053156

We have the final answer as

<h3>14.05 moles</h3>

Hope this helps you

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2 years ago
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nataly862011 [7]

Answer:

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And produces equal amount of H2.

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