Answer:
i. Molar mass of glucose = 180 g/mol
ii. Amount of glucose = 0.5 mole
Explanation:
<em>The volume of the glucose solution to be prepared</em> = 500 
<em>Molarity of the glucose solution to be prepared</em> = 1 M
i. Molar mass of glucose (
) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol
ii.<em> mole = molarity x volume</em>. Hence;
amount (in moles) of the glucose solution to be prepared
= 1 x 500/1000 = 0.5 mole
Hello @Lucysrv18,
How are you doing? In this case, we know that Electromagnetic waves that are visible to the human eye is neither made up of two electromagnetic waves nor three. Therefore B and C is incorrect.
These electromagnetic waves are divided and they are our final two options. For sure, i can say that the wavelengths in a visible electromagnetic wave are not divided into nine, but instead it is divided into 7.
The answer to your question is A.
Thank you,
Darian D.
The mole fraction is calculated using the formula:
mole fraction of component A = # of moles of component A / # of total moles of the solution.
A) number of moles of ethanol
To calculate the number of moles of ethanol, you need its density, which will permit you to determine the mass of the 10.00 ml, and then convert into moles using the molar mass of ethanol.
The normal density of ethanol is 0.789 g/ml
density = mass / volume => mass = density * volume = 0.789 g/ml * 10.00 ml = 7.890 g
Molar mass of ethanol = 46.07 g/mol
number of moles = mass / molar mass = 7.890g / 46.07 g/mol = 0.1713 mol
B) number of moles of water
density of water = 1.00 g/mol
mass of water = density * volume = 1.00 g/mol * 2.00 ml = 2.00 g
number of moles of water = mass / molar mass = 2.00 g / 18.0 g/mol = 0.111 mol
C) mole fraction
mole fraction of ethanol = number of moles of ethanol / number of moles of solution
number of moles of ethanol = 0.1713 / (0.1713 + 0.111) = 0.1713 / 0.2824 = 0.607
Answer: 0.607
The volume of the final solution may be calculated by adding the volume of the two components. This is 10.00 ml of ethanol + 2.00 ml of water makes 12.00 ml of solution.
It is not clear what the second question is meant for. Some context is missing. If you know density and you know maqss (or can calculate the mass from other data) you do not need to measure the volume.
question 1
moles = mass/molar mass of Al(OH)3
convert Kg to g
that is 1.09 x 1000=1090g
moles is therefore=1090g/78(molar mass of Al(OH)3)= 13.974 moles
question 2
moles=2.55g/327.2(molar mass of Pb(CO3)2= 7.79 x 10^-3 moles
from avogadro constant
1moles=6.02 x10^23 formula units
what about 7.79 x 10 ^-3
={(7.79 x 10^-3)moles x ( 6.02 x10^23)} /1 mole=4.69 x10^21 formula units
Can there be more than one? I think there is actually 3
