Answer:
<h2>A. 1</h2>
Step-by-step explanation:
Use:
|a| = a for a ≥ 0 or |a| = -a for a < 0
PEMDAS:
P Parentheses first
E Exponents
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
========================================
|8 - 7| · 4 + 3(-1)
= |1| · 4 - 3
= 1 · 4 - 3
= 4 - 3
= 1
is this a school qustion? if not
cool me too
Answer:
Let x be the number of silver medals.
As there were two more gold medals than silver ones, gold medals are x+2
We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.
Now, we can do an equation, as we know there were a total of 28 medals:
x + x + 2 + x + x + 2 - 4 = 28
And we isolate x:
4x = 28
x = 28/4 = 7
There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).
Answer:
8
Step-by-step explanation:
Since this is a rectangle, the opposite sides are congruent.
So the lengths of DG and EF are equal
3x + 5 = 29
3x = 29 - 5
3x = 24
x = 24/3
x = 8
