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ser-zykov [4K]
3 years ago
5

What is 3 square root of 125x12?

Mathematics
2 answers:
AlekseyPX3 years ago
3 0

Hi!

Square roots where the things under the root are multiplied (for example \sqrt{xy}) can be split up into \sqrt{x} * \sqrt{y}.

That's what I'm going to do in this case. I'm going to split \sqrt[3]{125x^{12}} into \sqrt[3]{125} * \sqrt[3]{x^{12}}

Now, the cube root of 125 is 5, because 5 * 5 * 5 = 125, and that is the definition of a cube root. (What multiplied 3 times by itself is equal to what's under the root)

Now to look at what the cube root of x^{12} is.

A cube root can be rewritten as x^{\frac{1}{3}}, same as a square root can be rewritten to x^{\frac{1}{2}}.

So if you take the cube root of x^12, you can change it to:

(x^{12} )^{1/3}

If you have a case like this, then you can multiply the two powers (in this case 12 and 1/3) to simplify it. 12 * 1/3 = 4, so you get x^4.

Now putting the two together, you get:

5x^{4} as your answer.

Hope this helped!

IRINA_888 [86]3 years ago
3 0
Cube root of of 125 is 5
cube root ofx^12 is x^4

so the answer is 5*x^4 or second choice

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3 0
4 years ago
A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 98% conf
adelina 88 [10]

Answer:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.1 represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.07 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.01;0;1)", and we got z_{\alpha/2}=2.326, replacing into formula (b) we got:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

3 0
4 years ago
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