Question

DJ Kenisha is making a playlist for a radio show; she is trying to decide what 6 songs to play and in what order they should be played. If she has her choices narrowed down to 5 reggae, 15 hip-hop, and 13 blues songs, and she wants to play an equal number of reggae, hip-hop, and blues songs, how many different playlists are possible? Express your answer in scientific notation rounding to the hundredths place.

Answer 1

Answer:

$8.19 \times 10^{4}$ different playlists are possible

Step-by-step explanation:

The order in which the songs are played is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

6 songs, so 2 reggae(from a set of 5), 2 hip hop(from a set of 15) and 2 blues(from a set of 13). So

$T = C_{5,2}C_{15,2}C_{13,2} = \frac{5!}{2!3!} \times \frac{15!}{2!13!} \times \frac{13!}{2!11!} = 10*105*78 = 81900$

In scientific notations:

4 digits after the first, which is 8, so:

$8.19 \times 10^{4}$ different playlists are possible