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Delvig [45]
2 years ago
7

Factor 3x^3 - 15x^2 + 18x.

Mathematics
1 answer:
Usimov [2.4K]2 years ago
8 0

Step-by-step explanation:

3 x^3-15x^2+18x 3(x^3-5x^2+6x)

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Answer:

the should be 12 feet

Step-by-step explanation:

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HELP QUICK! On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2). What is the lengt
Savatey [412]
They are both on the 2 of the y-axis, so now all you have to do is subrtact the x-axis coordinate of R by the x-axis coordinate of T. That would be (-6)-5 = -11. YOUR ANSWER IS NOT -11. Signs don't matter when your attempting to find distance. Just forget the negative sign(-). It has nothing to do with the answer.
YOUR ANSWER IS 11 UNITS!!!
7 0
3 years ago
ALG II NEED HELP QUICK! Will mark the brainliest answer
lbvjy [14]
I think it’s the second one because The formula would be
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4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

3 0
3 years ago
At 7pm last night ,the temperature was 10 degrees Fahrenheit. At 7am the next morning the temperature was negative 2. By how muc
stepladder [879]
The tempature decreased by 12, because 10-12= -2
6 0
3 years ago
Read 2 more answers
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