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Alina [70]
4 years ago
7

A scatterplot shows a strong, positive, linear relationship between the number of rebounds a basketball team averages and the nu

mber of wins that team records in a season. Which conclusion is most appropriate?
(A) A team that increases its number of rebounds causes its chances of winning more games to increase.
(B) If the residual plot shows no pattern, then it is safe to conclude that getting more rebounds causes more wins, on average.
(C) If the residual plot shows no pattern, then it is safe to conclude that getting more wins causes more rebounds, on average.
(D) If the r^2 value is close enough to 100%, then it is safe to conclude that getting more rebounds causes more wins, on average.
(E) Rebounds and wins are positively correlated, but we cannot conclude that getting more rebounds causes more wins, on average.
Mathematics
1 answer:
frutty [35]4 years ago
3 0

Answer: E

Conclusion E is most appropriate

Step-by-step explanation:

Rebounds and wins are positively correlated, but we cannot conclude that getting more rebounds causes more wins, on average.

Because if a scatterplot shows a strong, positive, linear relationship between two variables, then the two variables are positively correlated but there is no causation between them.

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A rectangular pool is 30 1/3 feet long and 12 1/2 feet wide. What is the area of the pool?
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5. Arrival problems usually follow a Poisson distribution, but in this case the time between arrivals of customers at a bank dur
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0.5 or 50%

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3 years ago
A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a
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Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)  [as x+y=14]

\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\

\Rightarrow x =(25 \times 14)/32=10.9375 grams

and y = 14-x= 14-10.9375=3.0625 grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\

\Rightarrow x =(50 \times 14)/57=12.28 grams

and y = 14-x= 14-12.28=1.72 grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

3 0
3 years ago
Use the numbers 7, 5, 6, and 3, only once each, to create an expression that equals 75. You may use addition, subtraction, multi
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 i got it ahhhhh: <span>6*(7+5))+3=75  is the expression you're looking for</span>
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4 years ago
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