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MrRa [10]
2 years ago
7

Can you please answer that + here's something that will make you laugh

Mathematics
1 answer:
lutik1710 [3]2 years ago
4 0

Answer:

The fourth and last answer is correct

Step-by-step explanation:

For the fourth one you have an exponent of an exponent, the base stays the same and the exponents get to be multiplied.

6^-1^16

For the last one both -8 x -2 and 8 x 2 equal 16.

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Counterexamples John says that if one side of an inequality is 0, you
Burka [1]
He may be wrong. If he was wrong, this is the example. 

0 < -10x

If we were to divide both sides by -10, even though the answer would be undefined or just end up as zero, it is just a common rule to always flip the sign whenever you divide or multiply by a negative. 

Don't quote me on it, but I think I'm right.

Hope this helped!

5 0
3 years ago
Read 2 more answers
What is the domain of the function y=2./-5?<br> OX-5<br> O X22<br> XX5<br> O x 10
lisabon 2012 [21]

D : x\geqslant 5

Thus the third option is the correct answer.

4 0
3 years ago
Is the answer 35 a5 b5 c5
Serga [27]
You almost had it instead of positive 35 it should be negative 35
so the answer should be -35a5b5c5
6 0
3 years ago
Simplify: [(-17) + 4 ÷ 2] ÷ [8 ÷ (-4) + 4] = ?​
lions [1.4K]

\large{\underline{\underline{\textsf{\textbf{\purple{Solution \: : - }}}}}}

\begin{gathered} \\  \\ \quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) + 4 \div 2 \bigg] \div \bigg[8 \div  \bigg( - 8 \bigg) + 4 \bigg]}  \\  \\ \end{gathered}

\red \divideontimes According to the "BODMAS rule" firstly performing "division".

\begin{gathered} \\  \\ \quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) + \dfrac{4}{2} \bigg] \div \bigg[ \dfrac{8}{ - 8} + 4 \bigg]}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) +  \cancel{\dfrac{4}{2}} \bigg] \div \bigg[ \: \cancel{\dfrac{8}{ - 8}} + 4 \bigg]}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) +  2 \bigg] \div \bigg[ - 1 + 4 \bigg]}  \\  \\ \end{gathered}

\red \divideontimes Now, performing "addition and opening round brackets".

\begin{gathered} \\  \\\quad\dashrightarrow{\sf \bigg[ - 17 +  2 \bigg] \div \bigg[ - 1 + 4 \bigg]}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf \bigg[  \:  - 15 \:  \: \bigg] \div \bigg[  \:  \:  3\:  \: \bigg]}  \\  \\ \end{gathered}

\red \divideontimes Now, opening "square brackets".

\begin{gathered} \\  \\ \quad\dashrightarrow{\sf { - 15  \div 3}}  \\  \\ \end{gathered}

\red \divideontimes Now, "dividing 15 by 3".

\begin{gathered}\\ \\ \quad\dashrightarrow{\sf {\dfrac{ - 15}{3} }}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf { \cancel{\dfrac{ - 15}{3}}}}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\underline{\underline{ \sf{\red{ - 5}}}}}  \\  \\ \end{gathered}

\begin{gathered}\bigstar{\underline{\boxed{\bf{\purple{Answer =  - 5}}}}}  \\  \\ \end{gathered}

∴ The Answer is -5.

\begin{gathered}\end{gathered}

\large{\underline{\underline{\textsf{\textbf{\purple{Learn More \: : - }}}}}}

\underline{\underline{\pmb{\mathbb{\red{BODMAS \: :}}}}}

<u>BODMAS</u> rule is an acronym used to remember the order of operations to be followed while solving expressions in mathematics.

It stands for :-

  • ↠ B - Brackets,
  • ↠ O - Order of powers or roots,
  • ↠ D - Division,
  • ↠ M - Multiplication 
  • ↠ A - Addition,
  • ↠ S - Subtraction.

It means that expressions having multiple operators need to be simplified from left to right in this order only.

\rule{200}2

\underline{\underline{\pmb{\mathbb{\red{BODMAS \:  RULE \: :}}}}}

First, we solve brackets, then powers or roots, then division or multiplication (whatever comes first from the left side of the expression), and then at last subtraction or addition.

  • ↠ Addition (+)
  • ↠ Subtraction (-)
  • ↠ Multiplication (×)
  • ↠ Division (÷)
  • ↠ Brackets ( )

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

6 0
3 years ago
Read 2 more answers
I need helpppppppppp!
8_murik_8 [283]

Answer:49y

Step-by-step explanation:

7 0
3 years ago
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