All categories

2 years ago

20. What is the greatest prime factor of 3^7+6^6 ?

Mathematics

1 answer:

mario62 [17]2 years ago

3 0

Answer:

Step-by-step explanation:

3^7 = 2187

6^6 = 46656

46656+2187=48843

Prime factors of 48843: 3, 3, 3, 3, 3, 3, 67

Factor tree:

48843

| \

16281 3

| \

5427 3

| \

1809 3

| \

603 3

| \

201 3

| \

67 3

You might be interested in

Convert to smaller parts if possible

Triss [41]

Answer:

Row 1 -

1/3, 1/2, 1/3, 2/3, 2/3, 8/15, 1/2.

Row 2 -

3/4, 3/4, 2/7, 21/25, 5/6, 7/9, 1/3.

Row 3 -

3/20, 7/20, 3/25, 3/5, 3/5, 1, 3/2 OR 1 1/2.

Hope this helped you out.

7 0

2 years ago

Help me please. Plzzzz.

Deffense [45]

16 is going to be right

8 0

2 years ago

Read 2 more answers

When dividing 878 by 31, a student finds a quotient of 28 with a remainder of 11. Check the students work, and use the check to

Liula [17]

878/3 is 28 with a remainder of 10! The error is when they subtracted 258-248 wrong

3 0

2 years ago

Read 2 more answers

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

8 0

2 years ago

Please help, please briefly explain, (awarded brainliest)

anastassius [24]

Answer:

Step-by-step explanation:

Its basically whatever point(s) meet exactly the on the x axis

4 0

2 years ago

Read 2 more answers