Answer:
A) Central angle has same measure as intercepted arc.
- mCE = mCD + mDE = 20° + 90° = 110°
B) Opposite angles of cyclic quadrilateral are supplementary.
- mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
- m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
- m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
- mQP = 360° - (90° + 76° + 72°) = 122°
C)
- m∠MLN = m∠MRN as same arc MN is intercepted
- m∠LMN is right angle as opposite side is diameter.
- ∠MNL is complementary with ∠MLN which is same as ∠MRN
- m∠MNL = 90° - 47° = 43°
D) Tangent secant angle is half of the intercepted arc.
<em>It seems wrong. Should be mQP instead of mQR</em>
- mQP = 2*m∠RQP = 2*74° = 148°
Answer:
angle AOD = 90⁰
BOD = 3x⁰
90⁰+3x⁰ = 180⁰( being straight angle)
3x = 180⁰-90⁰
3x = 90⁰
x = 90⁰/3
x = 30⁰
now
y⁰+139⁰ = 180⁰(being straight angle)
y⁰ = 180⁰-139⁰
y⁰ = 41⁰
Answer:
i think its D
Step-by-step explanation:
D
Answer:
the tenths place
Step-by-step explanation:
Answer:
i got 61.27
Step-by-step explanation:
quater circumference 
= 17.27
20+2+2+(20-11)+11+17.27 = 61.27
