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insens350 [35]
3 years ago
12

Howdy!

Mathematics
1 answer:
posledela3 years ago
8 0

Answer:

A) Central angle has same measure as intercepted arc.

  • mCE = mCD + mDE = 20° + 90° = 110°

B) Opposite angles of cyclic quadrilateral are supplementary.

  • mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
  • m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
  • m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
  • mQP = 360° - (90° + 76° + 72°) = 122°

C)

  • m∠MLN = m∠MRN as same arc MN is intercepted
  • m∠LMN is right angle as opposite side is diameter.
  • ∠MNL is complementary with ∠MLN which is same as ∠MRN
  • m∠MNL = 90° - 47° = 43°

D) Tangent secant angle is half of the intercepted arc.

<em>It seems wrong. Should be mQP instead of mQR</em>

  • mQP = 2*m∠RQP = 2*74° = 148°
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