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Hitman42 [59]
2 years ago
6

PLEASE HELP ME????( Brainlest) Please Show Work???

Mathematics
1 answer:
REY [17]2 years ago
3 0

Step-by-step explanation:

again, 2 unknowns.

x = number of 2- points baskets

y = number of 3- points baskets

we know they hit the basket 37 times in a so far unknown mixture of 2-point and 3- point throws.

x + y = 37

which gives us e.g.

x = 37 - y

and we know that with this unknown mixture they scored 80 points.

so,

2x + 3y = 80

as every successful 2-points throw scores 2 points, and every successful 3-points throw scores 3 points.

so, again our 2 equations :

x = 37 - y

2x + 3y = 80

remember, we prepared the first equation so that it gives us already an identity expressing one variable by the other. and that we use in the second equation :

2×(37 - y) + 3y = 80

74 - 2y + 3y = 80

74 + y = 80

y = 6

and from

x = 37 - y

we get

x = 37 - 6 = 31

so, they had 31 2-points throws and 6 3-points throws.

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In triangle $DEF,$ $\angle D = 30^\circ,$ $\angle F = 60^\circ,$ and $EF = 6.$ Find $DE + DF.$ [asy] unitsize(2 cm); pair D, E,
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Answer:

The answer is below

Step-by-step explanation:

In triangle DEF, ∠D = 30°, ∠F = 60° and EF = 6. Find DE + DF.

Solution:

A triangle is a polygon with three sides. There are different types of triangles such as isosceles triangle, scalene triangle equilateral triangle, right angled triangle.

In triangle DEF:

∠D + ∠E + ∠F = 180° (sum of angles in a triangle)

30 + ∠E + 60 = 180

∠E + 90 = 180

∠E = 180 - 90

∠E = 90°

This is a right angled triangle since one angle = 90° (∠E).

Using sine rule:

\frac{|EF|}{sin(D)}=\frac{|DE|}{sin(F)}  \\\\\frac{6}{sin(30)}=\frac{|DE|}{sin(60)}  \\\\|DE|=10.39\\\\\frac{|EF|}{sin(D)}=\frac{|DF|}{sin(E)}  \\\\\frac{6}{sin(30)}=\frac{|DF|}{sin(90)}  \\\\|DF|=12\\\\

Hence DE + DF = 12 + 10.39 = 22.39

6 0
3 years ago
3.024 x 106<br> 4.8 x 102
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Graph h(x)=7 sin x ?
DENIUS [597]

Answer:

The graph of h(x) is shown below.

Step-by-step explanation:

The given function is

h(x)=7\sin x

The general form of sine function is

f(x)=a\sin(bx+c)+d

Where, a is amplitude, b is period, c is phase shift and d is vertical shift.

So, the amplitude of the given function is 7, period is 1, phase shift is 0 and vertical shift is 0.

It means the minimum value of function is -7 and maximum value is 7.

Put x=0 in the given function.

h(x)=7\sin (0)=7(0)=0

Put  x=-\frac{\pi}{2} in the given function.

h(x)=7\sin (-\frac{\pi}{2})=-7(1)=-7

Put  x=\frac{\pi}{2} in the given function.

h(x)=7\sin (\frac{\pi}{2})=7(1)=7

Therefore the points on the function are (0,0), (-\frac{\pi}{2},-7),(\frac{\pi}{2},7).

The graph of function is shown below.

5 0
3 years ago
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