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3 years ago

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Is the equation

align="absmiddle" class="latex-formula"> an identity? Explain your reasoning.
A. Yes, because solving the equation gives a statement that is never true.

B. Yes, because solving the equation gives a statement that is always true.

C. No, because solving the equation gives a statement that is never true.

D. No, because solving the equation gives a statement that is always true.

help I don't know what an identity is or how to explain

1 answer:

evablogger [386]3 years ago

8 0

Given:

The equation is $-2(4-x)=2x+8$ .

To find:

Whether the given equation is an identity or not.

Solution:

If both sides of an equation are equal for all values of variables, then it is called identity.

We have,

$-2(4-x)=2x+8$

$LHS=-2(4-x)$

$LHS=-2(4)-2(-x)$

$LHS=-8+2x$

$LHS=2x-8$

Now,

$2x-8=2x+8$

On subtracting 2x from both sides, we get

$-8=8$

This statement is never true.

$LHS\neq RHS$

So, the given equation is not an identity because solving the equation gives a statement that is never true.

Therefore, the correct option is C.

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Here we have that the formula for the lateral surface area of a square pyramid is given as follows;

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h = Slant height

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Hence;

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Surface area of the pyramid = A + 1/2 × p × s

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Surface area of the pyramid = 335,673 cubit²

1 cubit = 20 in

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3 years ago

A survey of 1,107 tourists visiting Orlando was taken. Of those surveyed:

Ira Lisetskai [31]

Answer:

602 tourists visited only the LEGOLAND.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the tourists that visited LEGOLAND

-The set B represents the tourists that visited Universal Studios

-The set C represents the tourists that visited Magic Kingdown.

-The value d is the number of tourists that did not visit any of these parks, so: $d = 58$

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of tourists that only visited LEGOLAND, $A \cap B$ is the number of tourists that visited both LEGOLAND and Universal Studies, $A \cap C$ is the number of tourists that visited both LEGOLAND and the Magic Kingdom. and $A \cap B \cap C$ is the number of students that visited all these parks.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

There were 1,107 tourists suveyed. This means that:

$a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107$

We start finding the values from the intersection of three sets.

The problem states that:

36 tourists had visited all three theme parks. So:

$(A \cap B \cap C) = 36$

72 tourists had visited both LEGOLAND and Universal Studios. So:

$(A \cap B) + (A \cap B \cap C) = 72$

$(A \cap B) = 72 - 36$

$(A \cap B) = 36$

79 tourists had visited both the Magic Kingdom and Universal Studios

$(B \cap C) + (A \cap B \cap C) = 79$

$(B \cap C) = 79 - 36$

$(B \cap C) = 43$

68 tourists had visited both the Magic Kingdom and LEGOLAND

$(A \cap C) + (A \cap B \cap C) = 68$

$(A \cap C) = 68 - 36$

$(A \cap C) = 32$

258 tourists had visited Universal Studios:

$B = 258$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$258 = b + 43 + 36 + 36$

$b = 143$

268 tourists had visited the Magic Kingdom:

$C = 268$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$268 = c + 32 + 43 + 36$

$c = 157$

How many tourists only visited the LEGOLAND (of these three)?

We have to find the value of a, and we can do this by the following equation:

$a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107$

$a + 143 + 157 + 58 + 36 + 32 + 43 + 36 = 1,107$

$a = 602$

602 tourists visited only the LEGOLAND.

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4 years ago