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murzikaleks [220]
2 years ago
8

X-y=1/5 slope intercept form

Mathematics
1 answer:
Irina18 [472]2 years ago
6 0

Answer:

<u>y = x - 1/5</u>

Step-by-step explanation:

x - y = 1/5

5x - 5y = 1

5y = 5x - 1

<u>y = x - 1/5</u>

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What is the circumference of a circle with a diameter of 5 feet? use 3.14 for pi
artcher [175]

Answer:

15.7

Step-by-step explanation:

Circumference= πd

d= Diameter

7 0
3 years ago
EVALUATE !!!! ILL GIVE YOU BRAINLIST HAVE TO GET IT RIGHT !!!!
elena-s [515]

Answer:

<h2>12</h2>

Step-by-step explanation:

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8 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
2. The number of atoms of a particular chemical element is modelled by
____ [38]

9514 1404 393

Answer:

  a) 600

  b) see below

  c) 1.26 hours

Step-by-step explanation:

a) The value of y when x=0 is the coefficient of the exponential term:

  y = 600·3^(-0) = 600·1 = 600

There were 600 atoms to start.

__

b) see attached for a graph

__

c) The graph shows 150 atoms at t = 1.26, about 1.26 hours after the start of time counting.

If you want to find that value algebraically, substitute for y and solve for x. Logarithms are involved.

  150 = 600·3^(-x)

  150/600 = 3^(-x)

  log(1/4) = -x·log(3)

  x = -log(1/4)/log(3) = log(4)/log(3) ≈ 1.2618595

After about 1.26 hours, there were 150 atoms.

6 0
3 years ago
Six more than five times a number is at least twenty-one
kakasveta [241]
Lets say the number is x so we can make an equation
If is at least 21, that means it has to be greater then or equal to it.
6+5*x>=21
You can subtract 6 from both sides
5*x>=15
Then divide both sides by 5
x>=3
You can conclude that the number is greater then or equal to 3.
6 0
3 years ago
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