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2 years ago

X-y=1/5 slope intercept form

Mathematics

1 answer:

Irina18 [472]2 years ago

6 0

Answer:

y = x - 1/5

Step-by-step explanation:

x - y = 1/5

5x - 5y = 1

5y = 5x - 1

y = x - 1/5

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!!30 points!!

frosja888 [35]

Your answer would be 27 Gallons.

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2 years ago

Read 2 more answers

Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

6 0

2 years ago

Expand the expression using the distributive property. 2(5x – 3)

riadik2000 [5.3K]

Answer:

10x-6

Step-by-step explanation:

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2 years ago

I need help on 9 10 11 12 and 13 say the Writing to Explain Explain how you would write 5/6 as a percent

Kazeer [188]

9. 25
10. 70%
11. 30
12. Turn 5/6 to a decimal then multiply it times 100 and add your percent sign

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2 years ago

In the year 2019, Lee County used approximately 55 million gallons of water. Historical trends show that each year the water dem

Harlamova29_29 [7]

Answer:

Approximately 62 gallons of water will be used by Lee County by the year 2025.

Step-by-step explanation:

The amount, in millions gallons of water, spent by Lee County, in t years after 2019, is given by the following equation:

$P(t) = P(0)(1 + r)^{t}$

In which P(0) is the amount spent on 2019 and r is the increse rate, as a decimal.

In the year 2019, Lee County used approximately 55 million gallons of water.

This means that $P(0) = 55$

Historical trends show that each year the water demand is increasing by a rate of approximately 2.1%.

This means that $r = 0.021$

$P(t) = P(0)(1 + r)^{t}$

$P(t) = 55(1 + 0.021)^{t}$

$P(t) = 55(1.021)^{t}$

Approximately how many million gallons of water will be used by Lee County by the year 2025?

2025 is 2025 - 2019 = 6 years after 2019. So this is P(6).

$P(t) = 55(1.021)^{t}$

$P(6) = 55(1.021)^{6}$

$P(6) = 62.3$

Rounded to the nearest millions

Approximately 62 gallons of water will be used by Lee County by the year 2025.

3 0

3 years ago