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yuradex [85]
2 years ago
12

Find the area of the figure below.

Mathematics
1 answer:
Bad White [126]2 years ago
8 0

I am stuck on this too...
Maybe we can figure it out together

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Please answer both of these and show or tell me all your work
horrorfan [7]

Answer:

5. 1:6 2/5

6. 1:5

Step-by-step explanation:

5. each time in the table you multiply H by 6 2/5 ex.

column 4 , 100x6=600, 2/5 of 100 = 40 and the total is 640, so the contant of proprtionality is 6 2/5

6. in the table there is a point on 2:10 and can be simplified to 1:5 so for every minute 5 gallons of water will be used

hope this helps sorry if this inst what your looking for have a blessed day :)

8 0
3 years ago
The function ​f(x) models the average cost per​ unit, f(x), for Electrostuff to manufacture x units of Electrogadget IV. How man
andrey2020 [161]

Complete question is;

The function ​f(x) = (25000 + 280x)/x models the average cost per unit, f(x), for Electrostuff to manufacture x units of Electrogadget IV. How many units must the company produce to have an average cost per unit of $390?

Answer:

227 units

Step-by-step explanation:

We are given the function;

​f(x) = (25000 + 280x)/x

Where;

f(x) is the average cost per unit

x is the number of units

Now, we want to find out how many units the company must produce to have an average cost per unit of $390.

Thus, plugging $390 for f(x), we have;

390 = (25000 + 280x)/x

When we cross multiply, we get;

390x = 25000 + 280x

390x - 280x = 25000

110x = 25000

x = 25000/110

x ≈ 227

6 0
3 years ago
How do I solve for x?
saveliy_v [14]

 

\displaystyle\\\text{The equation is:}\\\\13^2-x^2=15^2-(14-x)^2\\\\13^2-x^2=15^2-(14^2-28x+x^2)\\\\13^2-x^2=15^2-14^2+28x-x^2)\\\\-x^2+x^2-28x=15^2-14^2-13^2\\\\-28x=225-196-169\\ \\-28x=-140~~~\Big|~\cdot(-1)\\\\28x=140\\\\x=\frac{140}{28}\\ \\\boxed{\bf x=5}



4 0
3 years ago
Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) i
Vaselesa [24]

Complete question:

Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?

Answer:

Here,

Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)

We are also told only 10 participants are available.

All 10 participants are being exposed to all five levels of the color variable in the same order.

Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.

Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.

But using counterbalancing technique, Dr. Lyte can avoid such an error.

6 0
4 years ago
Find the exact area of the circle with the given radius. r = 4.5 m
Alexus [3.1K]
The area of a circle is Pi * R^2 (or R * R).
Since we have our radius, R, we can solve.
With our given answer choices, we do not need to multiply R by Pi, instead we will square R, as that's our only option.
4.5 x 4.5 = 20.25.
Our area is now 20.25Pi.
Your answer is C.) 20.25Pi.
I hope this helps!
4 0
3 years ago
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