Alan swam 8 kilometers against the current in the same amount of time it took him to swim 16 kilometers with the current. The ra
1 answer:
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9514 1404 393
Answer:
- late only: 15
- extra-late only: 24
- one type: 43
- total trucks: 105
Step-by-step explanation:
It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.
For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.
Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.
__
a) 15 trucks carried only late
b) 24 trucks carried only extra late
c) 4+15+24 = 43 trucks carried only one type
d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out
Answer:
10th term of the sequence = 0.537
Step-by-step explanation:
First three terms of the sequence are → 5, 4, ..........
Ratio of 2nd and 1st term of the sequence =
Ratio of 3rd and 2nd term of the sequence =
=
Therefore, ratio between every successive term to the previous term is common.
Common ratio 'r' =
First term of the sequence 'a' = 5
nth term of a geometric sequence =
Therefore, nth term of the given term will be
Now we have to find the 10 term of the given sequence.
For n = 10,
= 0.53687
≈ 0.537
Therefore, 10th term of the sequence is 0.537