Answer:
import java.awt.Point;
public class Line{
private Point point1, point2;
public Line(Point p1, Point p2){
point1 = p1;
point2 = p2;
}
public Point getP1(){
return point1;
}
public Point getP2(){
return point2;
}
public String toString(){
return "[( The " + point1.x + "," + point1.y + "), (" + point2.x + "," + point2.y +")]";
}
public static void main(String args[]){
Line lineObj = new Line(new Point(7,9), new Point(6,2));
System.out.println(lineObj.toString());
}
}
Explanation:
- Declare the points inside the class Line.
- Initialize the getters and setters method for the class.
- Define a toString method that returns the information in a formatted manner.
- Inside the main method, initialize an object with some values.
- Display the information by calling the toString method.
C is going to be your answer
Im sorry i just need points
Answer:
int count =0;
for(int i=0;i<10;i++)
{
if(myArray[i]>=0)
{
count++;
}
}
cout<<"Number of positive integers is "<<count<<endl;
Explanation:
The above written loop is for counting positive integers in the myArray[].
For counting we have taken a count integer initialized with 0.On iterating over the array if the element is greater than or equal to 0 we consider it as positive and increasing the count.At the end printing the count.
Answer:
this one is not understandable you see but I think it's better than nothing to do with it tmzr I don't know what to say to someone who did you start the morning and you can not be able to get it to
