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3 years ago

In modern computer memory, each location is normally composed of one byte.

Computers and Technology

1 answer:

Paraphin [41]3 years ago

4 0

An actual parameter in a method call, or one of the values combined by an operator

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If you want a user to enter exactly 20 values, which loop would be the best to use?

Hitman42 [59]

Answer: For loop

Explanation:

Using the for loop we can get the exact number of values/outcomes we require.

For example: printf(enter 20 numbers");

for(int i=0; i<20;i++)

{

scanf("%d", &number);

}

So, this is an implementation of for loop in C. Using it we can enter exact 20 numbers not less or more than that.

Therefore, for loop is the answer.

4 0

3 years ago

Can someone please give me the 3.6 code practice answer I will mark you brainlyist

Stolb23 [73]

3.6 Code Practice Question:

Write a program to input 6 numbers. After each number is input, print the biggest of the number entered so far:

Answer:

nums = []

biggest = 0

for i in range(6):

num = int(input("Number: "))

nums.append(num)

if(i == 0):

print("Largest: "+str(nums[0]))

biggest = nums[0]

else:

if nums[i]>biggest:

print("Largest: "+str(nums[i]))

biggest = nums[i]

else:

print("Largest: "+str(biggest))

Explanation:

This question is answered using python

This line declares an empty list

nums = []

This line initalizes the biggest input to 0

biggest = 0

This iteration is perfoemed for 6 inputs

for i in range(6):

This prompts user for input

num = int(input("Number: "))

This appends user input to the list created

nums.append(num)

For the first input, the program prints the first input as the largest. This is implemented in the following if condition

if(i == 0):

print("Largest: "+str(nums[0]))

biggest = nums[0]

For subsequent inputs

else:

This checks for the largest input and prints the largest input so far

if nums[i]>biggest:

print("Largest: "+str(nums[i]))

biggest = nums[i]

else:

print("Largest: "+str(biggest))

3 0

2 years ago

Please help me I don't understand. It's Python.

Vitek1552 [10]

It’s , c probably sorry if I’m wrong

8 0

3 years ago

Read 2 more answers

Write a generator function named count_seq that doesn't take any parameters and generates a sequence that starts like this: 2, 1

-BARSIC- [3]

Answer:

#required generator function

def count_seq():

#starting with number 2. using string instead of integers for easy manipulation

n='2'

#looping indefinitely

while True:

#yielding the integer value of current n

yield int(n)

#initializing an empty string

next_value=''

#looping until n is an empty string

while len(n)>0:

#extracting first digit (as char)

first=n[0]

#consecutive count of this digit

count=0

#looping as long as n is non empty and first digit of n is same as first

while len(n)>0 and n[0]==first:

#incrementing count

count+=1

#removing first digit from n

n=n[1:]

#now appending count and first digit to next_value

next_value+='{}{}'.format(count,first)

#replacing n with next_value

n=next_value

#testing, remove if you don't need this

if __name__ == '__main__':

#creating a generator from count_seq()

gen=count_seq()

#looping for 10 times, printing next value

for i in range(10):

print(next(gen))

Explanation:

6 0

3 years ago

How fast is light? person that answers this will get points

Serhud [2]

299,792,458 metres per second

6 0

3 years ago